Figure 1: An image — an array or a matrix of pixels arranged in columns and rows.
In a (8-bit) greyscale image each picture element has an assigned intensity that
ranges from 0 to 255. A grey scale image is what people normally call a black and
white image, but the name emphasizes that such an image will also include many
shades of grey.
Figure 2: Each pixel has a value from 0 (black) to 255 (white). The possible range of the pixel
values depend on the colour depth of the image, here 8 bit = 256 tones or greyscales.
A normal greyscale image has 8 bit colour depth = 256 greyscales. A “true colour”
image has 24 bit colour depth = 8 x 8 x 8 bits = 256 x 256 x 256 colours = ~16
million colours.
Answer:
Bandwidth
Explanation:
Bandwidth is the rate of transfer of data in the given time. Its unit is Bit/sec.
It is used to measure the transfer rate of bit in a network.
Answer:
d) either e1 or e5
Explanation:
Here, the instruction i1 goes ahead in trying to open the given file through an input stream buffer reader. If the given file name is wrong, it will indicate that an e1 file is not found or if any other IO errors due to invalid stream, no disc in drive e5 IO exception will be drawn.
Answer:
mknod
Explanation:
When the user wants to configure a camera device on his Linux computer and the user recognizes that his device does not have a device-specific file. Thus, the user could use the mknod command on his computer to set up an equipment file because it is the command that is used to create a fresh file and these files are not the same as the normal file.
So, the following answer is correct according to the following scenario.
Answer:
struct node{
student data;
node* next;
};
Explanation:
The above written is the segment of code is the structure of node of the linked list.The data of the node is type student.So the data of the node of the linked list will consist of the student details and the next is the pointer which holds the address of the next node.
