The cost C of a long distance call as a function of the length t is C(t) = 0.25 + 0.07t and the number of minutes is 25 minutes
<h3>What are linear equations?</h3>
Linear equations are equations that have constant average rates of change. Note that the constant average rates of change can also be regarded as the slope or the gradient
<h3>How to determine the solution to the system?</h3>
A system of linear equations is a collection of at least two linear equations.
In this case, the given parameters are:
Charge for first minute = $.25
Rate for additional minute = $.07 per minute
Let the number of minutes be t and the total cost be C(t)
So, we have:
C(t) = Charge for first minute + Rate for additional minute * x
This gives
C(t) = 0.25 + 0.07t
When the total cost is $2, the equation becomes
0.25 + 0.07t = 2
Subtract 0.25 from both sides
0.07t = 1.75
Divide both sides by 0.07
t = 1.75/0.07
Evaluate the quotient
t = 25
Hence, the number of minutes is 25 minutes
Read more about linear equations at:
brainly.com/question/14323743
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