Salt flows into the tank at a rate of
(1/2 lb/gal) * (6 gal/min) = 3 lb/min
and flows out at a rate of
(Q(t)/60 lb/gal) * (6 gal/min) = 6Q(t) lb/min
The net rate of change of the amount of salt in the tank at time
is then governed by

Solve for
:


![\dfrac{\mathrm d}{\mathrm dt}[e^{6t}Q]=3e^{6t}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Be%5E%7B6t%7DQ%5D%3D3e%5E%7B6t%7D)


The tank starts with 10 lb of salt, so that Q(0) = 10. This gives us

so that the amount of salt in the tank at time
is given by

The range of the sprinkler will be the area of a circle with a radius of 40 feet.
area of circle = 
area of circle = 
area of circle =
=
answer:
I would need the equations
Answer: i am
Step-by-step explanation: Mark me brain and give 5 stars and a thank you
Answer:
A = 26
Step-by-step explanation:
sum of students = classA + classB + classC
let's say classA = A, classB = B, and classC = C
A + B + C = 66
class A has five more students than class B, so A = 5 more than B so A = 5+B
class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2
A + B + C = 66
A = 5+B
C = B-2
substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)
(5+B) + B + (B-2) = 66
3B + 3 = 66
subtract 3 from both sides to isolate the variable and its coefficient
3B = 63
divide both sides by 3 to solve for B
B = 21
A = 5 + B = 5 + 21 = 26