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Kruka [31]
3 years ago
5

Which of these processes involve the weakening of the attraction between particles

Chemistry
1 answer:
AveGali [126]3 years ago
3 0

Answer : The correct option is (3) Evaporation.

Explanation :

Evaporation : It is a process in which the liquid particles are converted to gaseous particles. The inter-molecular forces of attraction between the liquid particles will be weakened. As a result the phase change occurs.

Freezing  : It is a process in which a phase changes from liquid state to solid state.

Condensation : It is a process in which a phase changes from gaseous state to liquid state.

Crystallization : It is a process in which a solute particles get separated from the solvent in the form of crystals ( in solid phase).

Whereas in freezing, condensation and crystallization we are moving from one phase having weaker inter-molecular forces of attraction to another phase having stronger inter-molecular forces of attraction. So, in these processes strengthening of attraction between the particles takes place.

Hence, the correct answer is Evaporation.

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Answer:

\large \boxed{\text{D. 710 g}}

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\begin{array}{ccc}\textbf{Atoms} &\textbf{M}_{\textbf{r}} & \textbf{Mass/u}\\\text{2Na} & 23 & 46\\\text{1S} & 32 & 32\\\text{4O}&16 & 64\\&\text{TOTAL =} & \mathbf{142}\\\end{array}

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\text{Moles of Na$_{2}$SO}_{4} = \text{2.5 L solution} \times \dfrac{\text{2.0 mol Na$_{2}$SO}_{4}}{\text{1 L solution}} = \text{5.0 mol Na$_{2}$SO}_{4}

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\text{Mass of Na$_{2}$SO}_{4} = \text{5.0 mol Na$_{2}$SO}_{4} \times \dfrac{\text{142 g Na$_{2}$SO}_{4}}{\text{1 mol Na$_{2}$SO}_{4}} = \text{710 g Na$_{2}$SO}_{4}\\\\\text{You need } \large \boxed{\textbf{710 g}} \text{ of Na$_{2}$SO}_{4}

6 0
3 years ago
1. You have three molecules of glucose (3C6H12O6). How many carbon atoms do you have?. . A. 3. . B. 6. . C. 18. . D. 36. 2. Whic
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Explanation:

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     \gamma = \frac{C_p }{C_v}

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 The final  volume of the fluorocarbon gas isV_2 = 2V

  The initial  temperature of the fluorocarbon gas is  T_1  =  298.15 K

  The final  temperature of the fluorocarbon gas is T_2  =  248.44 K

   The initial  pressure is P_1  = 202.94\  kPa

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=>    C_p  = 42. 8 J/K\cdot mol

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