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4 years ago

Substances that cannot be separated and found on a periodic table

Chemistry

2 answers:

galina1969 [7]4 years ago

5 0

B. elements i hope that helps

GaryK [48]4 years ago

4 0

Substances that cannot be separated and found on a periodic table are elements.

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Which is an example of an exothermic process?

brilliants [131]

wrong it was E. Evaporation of water if your on plato btw

BRAINLY!!!!

4 0

3 years ago

Read 2 more answers

A tetrahedral carbon is ____________ hybridized while a linear carbon is ____________ hybridized. Two different compounds that h

nalin [4]

Answer:

1. Sp^3; Sp.

2. Isomers.

3. Weaker.

4. Atomic; hybrid.

5. Pi.

6. Electronegativity.

7. Resonance structures.

8. Sigma.

Explanation:

1. A tetrahedral carbon is Sp^3 hybridized while a linear carbon is Sp hybridized. A tetrahedral carbon typically comprises of four bonds that are 109. 5° apart while a linear carbon atom comprises of two (2) bonds that are 180° apart.

2. Two different compounds that have the same molecular formula are known as isomer. For example Butane and Isobutane, Methoxyethane and Propanol have the same molecular formula (numbers of hydrogen and carbon atoms) but different structural formula.

3. Pi (π) bonds are generally weaker than sigma (σ) bonds. This is because the orbital paths of Pi bonds are parallel thereby causing an overlap.

4. Hybridization is the combination of two or more atomic orbitals to form the same number of hybrid orbitals, each having the same shape and energy.

5. A Pi bond is formed by side-by-side overlap of two p orbitals.

6. The electronegativity is a measure of an atom’s attraction for electrons in a bond and indicates how much a particular atom "wants" electrons.

7. Two Lewis structures that have the same atomic placement and σ structure but a different arrangement of π electrons are called resonance structures.

8. All single bonds are Sigma bonds.

7 0

4 years ago

a 50.0 mL sample of KCl requires 22.40 mL of 0.0229 M Pb(NO3)2 in order to completely titrate it. What is the Molarity of the KC

garik1379 [7]

Answer:

0.02052M

Explanation:

First, we need to write a balanced equation for the reaction. This is illustrated below:

2KCl + Pb(NO3)2 → 2KNO3 + PbCl2

The following were obtained from the question:

Molarity of Pb(NO3)2 = 0.0229M

Volume of Pb(NO3)2 = 22.40 = 22.4/1000 = 0.0224L

Number of mole of Pb(NO3)2 =?

Recall:

Mole = Molarity x Volume

Mole of Pb(NO3)2 = 0.0229x0.0224

Mole of Pb(NO3)2 = 5.13x10^-4mole

From the equation,

1mole of Pb(NO3)2 required 2moles KCl.

Therefore, 5.13x10^-4mole of Pb(NO3)2 will require = 5.13x10^-4x2 = 1.026x10^-3mole of KCl.

Now we can use this amount (i.e 1.026x10^-3mole) to find the molarity of KCl. This is illustrated below:

Mole of KCl = 1.026x10^-3mole

Volume of KCl = 500mL = 50/1000 = 0.05L

Molarity =?

Molarity = mole /Volume

Molarity of KCl = 1.026x10^-3/0.05

Molarity of KCl = 0.02052M

8 0

4 years ago

If you digested 25 mg of pure ferrocene in nitric acid and then diluted the resulting solution up to 500 mL with 1% aqueous hydr

Vilka [71]

Answer:

1.345*10⁻⁴ mol/L

15.023 mg/L

Explanation:

The chemical <u>formula of ferrocene</u> is Fe(C₅H₅)₂, thus its molecular weight is:

55.845 g/mol + 10*12g/mol + 10 *1g/mol = 185.845 g/mol

The moles of Fe contained in 25 mg (or 0.025 g) of ferrocene are:

$0.025gFerrocene*\frac{1molFerrocene}{185.845g} *\frac{1mol Fe}{1molFerrocene}=1.345*10^{-4} molFe$

The final volume is 500 mL, or 0.5 L. So the iron concentration in mol/L is:

$\frac{1.345*10^{-4}molFe}{0.5L}= 2.69*10^{-4} mol/L$

We can convert that value into mg/L:

$2.69*10^{-4} \frac{molFe}{L} *\frac{55.845g}{1molFe}*\frac{1000mg}{1g}=15.023 mg/L$

6 0

4 years ago

Cerium (IV) ions are strong oxidizing agents in acid ic solution, oxidizing arsenio us acid to arsen ic acid accor ding to the f

kirill [66]

Answer:

0.2042 M is the original concentration of $Ce^{4+}$ (aq) in the titrating solution.

Explanation:

Mass of $As_2O_3$ = 0.217 g

Moles of $As_2O_3=\frac{0.217 g}{198 g/mol}=0.001096 mol$

1 mole of $As_2O_3$ have 2 mole of As and 1 mole of $H_3AsO_3$ have 1 mole of As.

So, from 1 mole of $As_2O_3$ we will have 2 moles of $H_3AsO_3$

Then from 0.001096 mol of $As_2O_3$ :

$2\times 0.001096 mol=0.002192 mol$ of $H_3AsO_3$

$2Ce^{4+}(aq)+H_3AsO_3(aq)+3H_2O(l)\rightarrow 2Ce^{3+}(aq)+H_3AsO_4(aq)+2H^+(aq)$

According to reaction, 1 mole of $H_3AsO_3$ reacts with 2 mole of cerium (IV) ions,then 0.002192 mol of

$\frac{2}{1}\times 0.002192 mol=0.004384 mol$ of cerium (IV) ions.

Volume of the acidic cerium{IV) sulfate = 21.47 ml =0.02147 L

1 mL = 0.001 L

$concentration = \frac{Moles}{Volume(L)}$

$[Ce^{4+}]=\frac{0.004384 mol}{0.02147 L}=0.2042 M$

0.2042 M is the original concentration of $Ce^{4+}$ (aq) in the titrating solution.

8 0

3 years ago