A thing used to tie something or to fasten things together.
"she brushed back a curl that had strayed from its bonds"
OR
An agreement with legal force, in particular.
<span>First, the child's weight must be converted from pounds to kilograms.
1 lb is equal to 0.453592 kg, so a 13 lb child weighs:
13 lb * 0.453592 kg/lb = 5.896696 kg
Next, use the child's converted weight to determine the mg dosage. The recommended dose is 15 mg per kg, so the recommended dose is:
15 mg/kg * 5.896696 kg = 88.45044 mg
Finally, determine how many mL are needed to provide the calculated mg dosage. One unit of the suspension is 80 mg/0.80 mL. In order to provide 88.45044 mg, you will need
88.45044 mg / 80 mg = 1.1056305 units of the suspension.
Multiplying this by the 0.80 mL portion of the unit of the suspension, you get the final mL dosage:
0.80 mL * 1.1056305 = 0.8845044 mL
A 13 lb child should receive 0.8845044 mL of the 80mg/.8mL suspension.</span>
In an average mass, each entry has equal weight. In a weighted average, we multiply each entry by a number representing its relative importance.
Assume that your class consists of 15 girls and 5 boys. Each girl has a mass of 54 kg, and each boy has a mass of 62 kg.
<em>Average mass</em> = (girl + boy)/2 = (54 kg + 62 kg)/2 = <em>58 kg</em>
<em>Weighted average (Method 1)
</em>
Use the <em>numbers of each</em> gender (15 girls + 5 boys)
,
Weighted average = (15×54 kg + 5×62 kg)/20 = (810 kg + 310 kg)/20
= 1120 kg/20 = <em>56 kg</em>.
If you put all the students on one giant balance, their total mass would be
1120 kg and the average mass of a student would be <em>56 kg.
</em>
<em>Weighted average (Method 2)
</em>
Use the <em>relative percentages</em> of each gender (75 % girls and 25 % boys).
Weighted average = 0.75×54 kg + 0.25×62 kg = 40.5 kg + 15.5 kg = <em>56 kg</em>
Each girl contributes 40.5 kg and each boy contributes 15.5 kg to the <em>weighted average</em> mass of a student.
Answer:
Mass ratio of sulfur and oxygen in compounds A and B is 3:2 which confirms that the mass ratios in the two compounds are simple multiples of each other
Explanation:
This question seeks to establish/confirm the law of multiple proportions which posits that elements combine to form different substances which are whole number multiples of each other. Best example of this plays out in the formation of several oxides of the same element. Looking at the ratio in which the elements combine in each of the oxides, we can assume that these ratios are simple whole number multiples of each other.
Now back to the question.
In substance A, we have 6 g of sulfur combining with 5.99 g of oxygen
Now, lest us calculate the ratio of the mass of sulfur to that of oxygen = 6g/5.99g = 1
Now let us calculate the mass ratio of sulfur to oxygen in the second compound = 8.6/12.88 = 0.668
Now the ratios in both compounds are 1 to 0.668. 0.668 to fraction is approximately 1/1.5.
So therefore, the ratio we are having would be 1:1/1.5 or 1:0.668
This is same as 1/(1÷1.5) which is 1.5/1 or simply 3/2
This gives a ratio of approximately 1.5 to 1 or 3 to 2
The ratio 3 to 2 indicates that the mass ratios in both com pounds are simple multiples of each other