Need help with these problems

Of the 60 animals on a certain farm, 2/3 are either pigs or cows. How many of the animals are cows? (1) The farm has more than t

mario62 [17]

Answer:

Step-by-step explanation:

$\frac{2}{3}of total=$ either cow or pigs

$\frac{2}{3}of 60=$

$\frac{2}{3} X 60=40$

Either pigs or cow = 40

(1) Let number of pigs be x

then number of cows >twice of pigs = 2x

number of pigs + number of cows = 40

number of cows = 40 -x

40-x > 2x

40 > 3x

x < $\frac{40}{3}$

x < 12.33

nearest integral number is 12

so its 12

so number of pigs will be 12 so that number of cows = 40 -12 = 28

which is more than twice of number of pigs

28 > 2( 12) = 24

(2) number of pigs + number of cows = 40

for x>12

number of cows = 40 -x

x > 12

-x < -12

adding 40 both sides

40-x < 40-12

number of cows <28

7 0

4 years ago

Mary and Benjamin are driving to their friend Paar's house for a berday party Mary drives 9

SpyIntel [72]

Answer:

3.2 miles

Step-by-step explanation:

Given that Mary drives 9 miles north and 6 miles east to get there, the resultant miles will be achieved by using pythagorean theorem

R = sqrt ( 9^2 + 6^2 )

R = sqrt ( 81 + 36 )

R = sqrt ( 117 )

R = 10.82 miles

while Ben drives 3 miles south and 7 miles west

Use the same pythagorean theorem to find the resultant displacement

R = sqrt ( 3^2 + 7^2 )

R = sqrt ( 9 + 49 )

R = sqrt ( 58 )

R = 7.62 miles

The difference in miles to where Mary and Benjamin live will be difference in the resultant displacement of the two

Difference = 10.82 - 7.62 = 3.2 miles.

Therefore, Mary live 3.2 miles from Benjamin.

6 0

4 years ago

David keeps records of his monthly earnings. Last month he worked 120 hours and earned $2700. This month he worked 100 hours and

lianna [129]

F(x) = 20x+300
you sub in the x values (120 hours and 100 hours) for each equation
the only one they both work for is the last one
f(x) = 20x + 300
f(100) = (20 * 100) + 300 = 2000 + 300 = 2300

f(120) = (20 * 120) + 300 = 2400 + 300 = 2700

8 0

3 years ago

Read 2 more answers

Hilary is making slime for a class project

Fynjy0 [20]

4:6
8:12
Are the answers

5 0

2 years ago

Solve using a system of equations. Tickets to a local movie were sold at $6.00 for adults and $4.50 for students. If 110 tickets

Marrrta [24]

Answer:

The number of adults tickets is 80 and the number of students tickets is 30

Step-by-step explanation:

Given as :

The tickets price for adults = $6.00

The tickets price for students = $4.50

Total number tickets were sold = 110

Total Price of 110 tickets = $615.00

Now,

Let The number of adults tickets sold = A

The number of students tickets sold = S

So, according to question

A + S = 110

And 6 A + 4.5 S = 615

Or, 6 A + 6 S = 660 .....1

6 A + 4.5 S = 615 ......2

Solving the equations

( 6 A + 6 S ) - ( 6 A + 4.5 S ) = 660 - 615

Or, ( 6 A - 6 A ) ( 6 S - 4.5 S ) = 45

or, ( 6 S - 4.5 S ) = 45

or, 1.5 S = 45

∴ S = $\frac{45}{1.5}$

I,e S = 30

Put the value of S in eq 1

So, 6 A + 6 × 30 = 660

Or, 6 A = 660 - 180

Or 6 A = 480

∴ A = $\frac{480}{6}$

I.e A = 80

Hence The number of adults tickets is 80 and the number of students tickets is 30 . Answer

4 0

3 years ago