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diamong [38]
2 years ago
6

Marion is making trail mix for a group camping trip. She buys 3 pounds of granola for $3 per pound and 0.75 pounds of raisins fo

r $2 per pound. What equation can you use to find the price per pound of the trail mix? 3(3)(0.75)(2) = (3 + 0.75)x 3(3) + 0.75(2) = (3 + 0.75)x 3(3)(0.75)(2) = (3 + 0.75) + x 3(3) + 0.75(2) = (3 + 0.75) + x
Mathematics
2 answers:
lutik1710 [3]2 years ago
8 0

Answer:

B

Step-by-step explanation:

3(3) + 0.75(2) = (3 + 0.75)x

Valentin [98]2 years ago
3 0

Answer:

Step-by-step explanation:

77

You might be interested in
Emma has 18 yellow flowers and 30 white flowers. She wants to split them into vases in equal groups. What is the largest number
likoan [24]

Answer:

Flowers, yellow flowers, white flowers, group, GCF

For this case we have 18 yellow flowers and 30 white flowers, we must find a number that represents the largest number of groups of flowers that can be formed, bearing in mind that each group must contain the same number of yellow and white flowers. To do this, we must find the GCF (Greatest Common Factor) of yellow flowers and white flowers.

We look for the factors of 18, that is, the numbers for which 18 is divisible, these are:

18, 9, 6, 3, 2 and 1

We look for the factors of 30, that is, the numbers for which 30 is divisible, these are:

30, 15, 10, 6, 5, 3, 2, 1

Thus, we can see that GCF of both numbers is 6.

Then we can form 6 groups of flowers. To know the amount of flowers of each color in each group, we divide:

Thus, 6 groups of flowers can be formed with 3 yellow flowers and 5 white flowers each.

Answer:

The largest number of groups that can be done is 6.

Read more on Brainly.com - brainly.com/question/950582#readmore

Step-by-step explanation:

4 0
2 years ago
Consider the function V=g(x), where g(x) =x(6-2x)(8-2x), with x being the length of a cutout in cm and V being the volume of an
Andrej [43]

Answer:

The maximum volume of the open box is 24.26 cm³

Step-by-step explanation:

The volume of the box is given as V=g(x), where g(x)=x(6-2x)(8-2x) and 0\le x\le3.

Expand the function to obtain:

g(x)=4x^3-28x^2+48x

Differentiate  wrt  x to obtain:

g'(x)=12x^2-56x+48

To find the point where the maximum value occurs, we solve

g'(x)=0

\implies 12x^2-56x+48=0

\implies x=1.13,x=3.54

Discard x=3.54 because it is not within the given domain.

Apply the second derivative test to confirm the maximum critical point.

g''(x)=24x-56, g''(1.13)=24(1.13)-56=-28.88\:

This means the maximum volume occurs at x=1.13.

Substitute x=1.13 into g(x)=x(6-2x)(8-2x) to get the maximum volume.

g(1.13)=1.13(6-2\times1.13)(8-2\times1.13)=24.26

The maximum volume of the open box is 24.26 cm³

See attachment for graph.

6 0
3 years ago
Plz..... Solve this questions for me...
faust18 [17]

6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================

7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================

8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10

3 0
2 years ago
Rebecca has 3 pairs of running shoes.She bought new shoelaces for each pair.How many shoelaces did she buy?
kvasek [131]

Answer: 6 shoelaces

Step-by-step explanation:

Since 1 pair of shoes has 2 shoelaces, 3 x 2 = 6

3 pairs x 2 shoelaces = 6 shoelaces

Hope this helped!

P.S. PLS give brailiest! I only have one brainliest!!

4 0
3 years ago
Read 2 more answers
Please help me w the answer
evablogger [386]

Answer:

\frac{2(x-6)(x-10)}{(x-4)(x-5)}

Step-by-step explanation:

In essence, one needs to work their way backwards to solve this problem. Use the information to construct the function.

The function has verticle asymptotes at (x = 4) and (x = 5). This means that the denominator must have (x - 4) and (x - 5) in it. This is because a verticle asymptote indicates that the function cannot have a value at these points, the function jumps at these points. This is because the denominator of a fraction cannot be (0), the values (x - 4) and (x - 5) ensure this. Since if (x) equals (4) or (5) in this situation, the denominator would be (0) because of the zero product property (this states that any number times zero equals zero). So far we have assembled the function as the following:

\frac{()}{(x-4)(x-5)}

The function has x-intercepts at (6, 0), and (0, 10). This means that the numerator must equal (0) when (x) is (6) or (10). Using similar logic that was applied to find the denominator, one can conclude that the numerator must be ((x - 6)(x-10)). Now one has this much of the function assembled

\frac{(x-6)(x-10)}{(x-4)(x-5)}

Finally one has to include the y-intercept of (0, 120). Currently, the y-intercept is (60). This is found by multiplying the constants together. (6 * 10) equals (60). One has to multiply this by (2) to get (120). Therefore, one must multiply the numerator by (2) in order to make the y-intercept (120). Thus the final function is the following:

\frac{2(x-6)(x-10)}{(x-4)(x-5)}

6 0
3 years ago
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