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madam [21]
3 years ago
5

What inequalities is not true when x = -2

Mathematics
1 answer:
Sholpan [36]3 years ago
4 0
A= -6(-2) < -10
12 < -10
NOT TRUE

B= -2(-2) > -3
4 > -3
TRUE

C= -2/4 < 0
-1/2 < 0
TRUE

D= -4 < (-2)-5
-4 < -7
TRUE

So the answer is A

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In one day Anne traveled five times the sum of the number of hours Brian traveled and two. together they travel 20 hours find th
den301095 [7]
Let the number of hours Brian travelled = X
Then the number of hours Anne traveled = 5X + 2
Since they together travelled 20 hours, then
X + ( 5X + 2) = 20
X + 5X + 2 = 20
6X + 2 = 20
6X = 20 - 2
6X = 18
X = 18/6
   = 3 hours.
So brian travels for a period of 3 hours.
Now the number of hours Anne travelled = 5X +2
                                                                 = (5 * 3) + 2
                                                                 = 15 + 2
                                                                 = 17 hours.
 
3 0
3 years ago
Find the slope of the line | (3) | A) B) C) را با اب D)​
Travka [436]
Hi!


Could you provide a picture of the graph please??


Otherwise I have a hard time answering :/


But I’m really good a graphs! Just provide a picture and I will definitely help!


Many lucks coming your way!
8 0
3 years ago
Jessica was surveying students about their use of the new language lab in a school.Which question in the survey is a statistical
defon
The answer is <span>3.How many hours do you spend each week in the language lab? because the question asked about the use of the lab not where it is. hope it helps : )</span>
5 0
3 years ago
Read 2 more answers
The temperature at a point (x,y,z) is given by t(x,y,z)=200e−x2−y2/4−z2/9t(x,y,z)=200e−x2−y2/4−z2/9, where tt is measured in deg
yulyashka [42]
First find the gradient by using partial derivatives.

T_x = (-2x)200 e^{(-x^2 -y^2/4 -z^2/9)} \\  \\ T_y = (-\frac{1}{2}y)200 e^{(-x^2 -y^2/4 -z^2/9)} \\  \\ T_z = (-\frac{2}{9}z)200 e^{(-x^2 -y^2/4 -z^2/9)}

Sub in given point (0,-1,2) for x,y,z
∨T = (T_x, T_y,T_z) = (0,100e^{-25/36, \frac{-800}{9} e^{-25/36})

Next, find unit vector from directional vector (0,-1,2) --> (-3,4,-3)
v = (-3-0, 4-(-1), -3-2) = (-3,5,-5) \\  \\ ||v|| = \sqrt{(-3)^2 + 5^2 + (-5)^2} = \sqrt{59} \\  \\ u = (\frac{-3}{\sqrt{59}}, \frac{5}{\sqrt{59}},\frac{-5}{\sqrt{59}})

Finally, use dot product on gradient and unit vector to get directional rate of change.
Answer is approx 61.398 
8 0
3 years ago
In the function y = 4x + 3, what is the value of the dependent variable if the value of the independent variable is 3?
emmainna [20.7K]
15=4(3)+3 so 15 is the value of the dependent variable
6 0
2 years ago
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