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3 years ago

Does the communicative property of addition apply one adding two negative integers. Explain

2 answers:

5 0

Yes, it does apply to adding negative integers because the communative property of addition says that changing the order does not change the sum.

GarryVolchara [31]3 years ago

3 0

Yes, it does apply when you add negative integers

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Help me quick please --4x-7-3x+4=25

V125BC [204]

Answer:

Step-by-step explanation:

4x - 7 - 3x + 4 =25

=> 4x - 3x = 25 + 7

=> x = 32 (Ans)

3 0

3 years ago

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Each day for two workweeks (10 days total), George weighs 4 bags from that day’s production. If the average of the means is 14 o

alina1380 [7]

Answer:

a. 13.7084 oz.

Step-by-step explanation:

Formula for Lower Control Limit =

(LCL = x-bar - A²R-bar)

x - bar = 14 oz

A2 = 0.729

R - bar = 0.4 oz

= 14 - 0.729 × 0.4

= 14 - 0.2916

= 13.7084oz

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3 years ago

Daniel borrows $2,500 at 6% simple interest for 5 years. How much is daniel going to pay in interest. May I please get help I ha

Sergio039 [100]

Answer:

2500 x 6/100 = 150

150 x 5 = 750

2500 + 750 = 3 250

Step-by-step explanation:

You first have to determine the interest for one year. We know that a percentage means a 100 so we are going to use 6/100. You then have to multiple that by the original amount, you will then get your answer. After obtaining your answer your will multiple it by the number of years which is 5, once you get your answer add it to the original amount. Then you are all set.

5 0

3 years ago

ASAP JUST ANSWER THX

Andrei [34K]

Answer:

Step-by-step explanation:

f(-9) = 25

g(-1) = 21

7 0

3 years ago

Read 2 more answers

I need some help with math

Irina18 [472]

Answer:

$(y-7)^2+(x-2)^2=16$

and

$(x+2)^2+(y-15)^2 = 9$

Step-by-step explanation:

The standard equation of a circle is $(x-h)^2+(y-k)^2=r^2$ where the coordinate (h,k) is the center of the circle.

Second Problem:

We can start with the second problem which uses this info very easily.
(h,k) in this problem is (-2,15) simply plug these into the equation. $(x--2)^2+(y-15)^2=r^2$ .
We can also add the radius 3 and square it so it becomes 9. The equation.
This simplifies to $(x+2)^2+(y-15)^2 = 9$ .

First Problem:

The first problem takes a different approach it is not in standard form. But we can convert it to standard form by completing the square.
$y^2-14y+x^2-4x+37=0$ first subtract 37 from both sides so the equation is now $y^2-14y+x^2-4x=-37$ .
$y^2-14y+x^2-4x+37=0$ by adding $(-\frac{b}{2a} )^2$ to both the x and y portions of this equation you can complete the squares. $(-\frac{b}{2a})^2=(-\frac{-14}{2(1)})^2$ and $(-\frac{-4}{2(1)})^2$ which equals 49 and 4.
Add 49 and 4 to both sides and the equation is now: $y^2-14y+49+x^2-4x+4=-37+49+4$ You can simplify the y and x portions of the equations into the perfect squares or factored form $(y-7)^2$ and $(x-2)^2$ .
Finally put the whole thing together. $(y-7)^2+(x-2)^2=16$ .

I hope this helps!

5 0

3 years ago