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Zanzabum
3 years ago
8

I need some help with math

Mathematics
1 answer:
Irina18 [472]3 years ago
5 0

Answer:

(y-7)^2+(x-2)^2=16

and

(x+2)^2+(y-15)^2 = 9

Step-by-step explanation:

The standard equation of a circle is (x-h)^2+(y-k)^2=r^2 where the coordinate (h,k) is the center of the circle.  

Second Problem:

  1. We can start with the second problem which uses this info very easily.
  2. (h,k) in this problem is (-2,15) simply plug these into the equation. (x--2)^2+(y-15)^2=r^2 .
  3. We can also add the radius 3 and square it so it becomes 9. The equation.
  4. This simplifies to (x+2)^2+(y-15)^2 = 9.

First Problem:

  1. The first problem takes a different approach it is not in standard form. But we can convert it to standard form by completing the square.
  2. y^2-14y+x^2-4x+37=0 first subtract 37 from both sides so the equation is now y^2-14y+x^2-4x=-37.
  3. y^2-14y+x^2-4x+37=0 by adding (-\frac{b}{2a} )^2 to both the x and y portions of this equation you can complete the squares. (-\frac{b}{2a})^2=(-\frac{-14}{2(1)})^2 and (-\frac{-4}{2(1)})^2 which equals 49 and 4.
  4. Add 49 and 4 to both sides and the equation is now:y^2-14y+49+x^2-4x+4=-37+49+4 You can simplify the y and x portions of the equations into the perfect squares or factored form (y-7)^2 and (x-2)^2.
  5. Finally put the whole thing together. (y-7)^2+(x-2)^2=16.

I hope this helps!

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