All categories

4 years ago

Longitudinal sound waves cannot propagate through

Physics

1 answer:

SVEN [57.7K]4 years ago

7 0

<h2>Answer: Vacuum</h2>

Longitudinal sound waves are mechanical waves, that is, <u>they necessarily need a medium to propagate</u> (unlike electromagnetic waves) therefore they cannot propagate in vacuum.

This is because in this type of longitudinal waves, the vibration is parallel to the propagation direction of the wave itself. These disturbances are due to the <u>successive compressions of the medium</u>, where the particles move back and forth in the same direction as the wave.

You might be interested in

Why is being geosynchronous important for telecommunications satellites

Lelu [443]

Because any antenna on the ground that uses a satellite has to stay pointed at the satellite.

If the satellite is moving in the sky, then the antenna has to keep moving to follow it.

But if the satellite APPEARS to be motionless in the sky, then the antenna on the ground can be aimed once, and it doesn't have to be moved after that. "Set it and forget it."

There would be no TV satellites if everybody who wanted to use it had to keep moving their little dish to keep the TV picture coming in.

6 0

3 years ago

Problem PageQuestion A cylinder measuring 2.3cm wide and 2.7cm high is filled with gas. The piston is pushed down with a steady

Alexandra [31]

Jehedhdhsh dbdbdbdbdbdbdbebddnsbdb
Dhdhdbdbdbdbdhfhbdbddbdbdbdbdbdbsbsbsbdbdbdb d s DVD’s

8 0

4 years ago

When switched on, the grinding machine accelerates from rest to its operating speed of 3550 rev/min in 10 seconds. When switched

Paraphin [41]

Answer:

During start total turns

$N_1 = 296 turn$

After half of the time total turns

$N_3 = \frac{29.6 + 0}{2}(5) = 74 turns$

Total number of turns during it stop

$N_2 = \frac{59.17 + 0}{2}(31) = 917 turn$

After half of the time total turns

$N_4 = 688 turns$

Explanation:

Initially the machine is at rest and then starts rotating with speed 3550 rev/min

now we will have

$f = \frac{3550}{60} = 59.17 rev/s$

now we know that it took 10 s to reach the speed

so angular acceleration is given as

$\alpha = \frac{\omega_f - \omega_i}{t}$

$\alpha = \frac{59.17- 0}{10} = 5.917 rev/s^2$

now it stops in 31 s so the angular deceleration is given as

$\alpha_2 = -\frac{59.17}{31} = -1.91 rev/s^2$

now initially number of turn to reach the given speed

$N_1 = \frac{59.17 + 0}{2}(10) = 296 turn$

number of turns during it stop

$N_2 = \frac{59.17 + 0}{2}(31) = 917 turn$

Now during startup speed after t = 5 s is given as

$\omega_1 = (5.917)(5) = 29.6 rev/s$

$N_3 = \frac{29.6 + 0}{2}(5) = 74 turns$

now during it stop the speed after half the time is given as

$\omega_2 = 59.17 - (1.91)(15.5) = 29.56 rev/s$

now the number of turns is given as

$N_4 = \frac{59.17 + 29.56}{2}(15.5)$

$N_4 = 688 turns$

5 0

3 years ago

Why material selection is important to design and manufacturing?

Darina [25.2K]

Answer:

You want your product to be as strong and as long lasting as possible. There are also the safety implications to consider. You see, dangerous failures arising from poor material selection are still an all too common occurrence in many industries.

Explanation:

5 0

3 years ago

Read 2 more answers

Find the equivalent resistance of this

MAXImum [283]

Explanation:

1/R = 1/R1 + 1/ R2

1/R = 1/960 + 1/640

1/R = 5 / 1920

So , Req = 384 + R3

Req = 384 + 180

$\huge\red{A}\pink{N}\orange{S}{W}\blue{E}\green{R}$

7 0

2 years ago