The free body diagram shows a box being pulled to the left up a 25-degree incline
2 answers:
The question is incomplete but still I answer to assume your thinking.
The picture is attached below!.
Here,
F is the force with which you pull up the incline.
N is the normal force.
w is the weight acting downward.
Axis are mentioned in the attached picture.
Concept:
You can see there is no movement of object in the y-direction that means acceleration is zero in y-direction, sum of all the forces in y-direction equal to zero.
According to newton second law,
<span>∑ F = ma
</span>As, acceleration is zero in y-direction, so right hand side is zero in the above equation.
<span>∑ F = 0</span>
N-wcosθ=0
N= m*g*cos25°
N= m*(9.8)*(0.9063)
N= 8.8817*m
By putting the value of mass(m)(not given in the question) you will get the answer.
Hopefully, this is the answer of your question.
The picture is attached below!.
Here,
F is the force with which you pull up the incline.
N is the normal force.
w is the weight acting downward.
Axis are mentioned in the attached picture.
Concept:
You can see there is no movement of object in the y-direction that means acceleration is zero in y-direction, sum of all the forces in y-direction equal to zero.
According to newton second law,
<span>∑ F = ma
</span>As, acceleration is zero in y-direction, so right hand side is zero in the above equation.
<span>∑ F = 0</span>
N-wcosθ=0
N= m*g*cos25°
N= m*(9.8)*(0.9063)
N= 8.8817*m
By putting the value of mass(m)(not given in the question) you will get the answer.
Hopefully, this is the answer of your question.
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Answer:
47.68 x 10²³ or 4.768 x 10²⁴ copper atoms
Explanation:
Given:
Radius of the copper sphere (r) = 0.935 in
<em>First convert the radius from inches to centimeters</em>
1 in = 2.54cm
0.935in = 0.935 x 2.54cm = 2.3749cm
∴ r = 2.3749cm
<em>Calculate the volume of the copper sphere as follows</em>
Volume = [substitute r = 2.3749cm and π = 22 / 7]
Volume =
Volume = 56.108cm³
<em>From the volume and given density, calculate the mass of the copper sphere </em>
mass = density x volume [density = 8.96g/cm³]
mass = 8.96 x 56.108 = 502.73g
<em>From known facts</em>
1 mole of copper = 63.5g of copper = 6.022 x 10²³ copper atoms.
Then,
502.73 g of copper = = 47.68 x 10²³ copper atoms
Therefore, the sphere contains 47.68 x 10²³ copper atoms