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3 years ago

What are equivelent froctions of. 7/12

Mathematics

2 answers:

Tatiana [17]3 years ago

3 0

I think that some equivalent fractions to 7/12 is 14/24, 21/36 and 28/48. Hope this helps!!

MakcuM [25]3 years ago

3 0

14/24 & 28/48 & 36/96

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The quotient of a number y and 2. A. 2/y B. 2(y) C. 2 + y D. y/2

Virty [35]

Answer:

The answer to your problem is B.

7 0

2 years ago

An engineer is planning a new water pipe installation. The circular pipe has a diameter of d=20\text{ cm}d=20 cmd, equals, 20, s

aivan3 [116]

Answer: The answer is 314.28 cm² (approx.).

Step-by-step explanation: Given that an engineer is going to install a new water pipe. The diameter of this circular pipe is, d = 20 cm.

We need to find the area 'A' of the circular cross-section of the pipe.

Given, diameter of the circular section is

$\textup{d}=20~\textup{cm}.$

So, the radius of the circular cross-section will be

$\textup{r}=\dfrac{\textup{d}}{2}=\dfrac{20}{2}=10~\textup{cm}.$

Therefore, cross-sectional area of the pipe is

$\textup{A}=\pi \textup{r}^2=\dfrac{22}{7}(10)^2=\dfrac{2200}{7}=314\dfrac{2}{7}=314.28~.~.~.~\textup{cm}^2.$

Thus, the answer is 314.28 cm² (approx.).

4 0

4 years ago

I don’t know how to do it can someone help me?

frozen [14]

Answer:f(g(0))= 1/5

g(f(0))= 7

Step-by-step explanation:

for f(g(0))=you solve for g(x) but you plug in 0 for x so g(0)= 8(0)+3

so now you plug in the answer of the function of g(x) witch is 3 and plug it in as the x for F(x) so f(3)= 1/(3)+2

= 1/5

so f(g(0)) is equal to 1/5

Now for G(f(0)) you solve for f(x) by pluging 0 for x so F(0)= 1/(0)+2

=1/2

now you plug in 1/2 for the x of g(x) so g(1/2)= 8(1/2)+3

= 4+3

so g(f(0)) is equal to 7

Hope this helps:)

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3 years ago

GAMES At the Befrway Outlet store, you buy x

gizmo_the_mogwai [7]

Y= 13x+4x
y equals the amount of money spent

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3 years ago

What is the value of x in this equation? 8x + 40 = 180

antiseptic1488 [7]

Answer:

17.5

Step-by-step explanation:

180 = 40+ 8x

140 = 8x

17.5 = x

6 0

3 years ago

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