Hi there!

To calculate the tension, we must calculate the acceleration of the system.
Begin with a summation of forces:
∑F = -M₁gsinФ + T - T + M₂g
Simplify and solve for acceleration: (Tensions cancel out)

Plug in values. Let g = 10 m/s²

Now, to find tension, let's sum up the forces acting on ONE block. For simplicity, we can look at the hanging block:
∑F = -T + W
ma = -T + W
Rearrange to solve for T:
T = W - ma
We know the acceleration, so plug in the values:
T = (8)(10) - (8)(5.91) = 32.73 N
Answer:
32 m and -2.4 m/s
Explanation:
Given:
v₀ = 25 m/s
t = 2.8 s
a = -9.8 m/s²
Find: Δy, v
Δy = v₀ t + ½ at²
Δy = (25 m/s) (2.8 s) + ½ (-9.8 m/s²) (2.8 s)²
Δy = 31.6 m
v = at + v₀
v = (-9.8 m/s²) (2.8 s) + 25 m/s
v = -2.44 m/s
Rounded to two significant figures, the bullet reaches a height of 32 m and a velocity of -2.4 m/s.
Answer:
4 131.05 kilometers
Explanation:
You should know the rest!!!!!!!!!!!!!!!!!!!!!
1. As you push a cereal box across a tabletop, the sliding friction acting on the cereal box_____.
<span> d.) acts in the direction opposite of motion. </span>
2.) Projectile motion is caused by____________.
d.) the downward force of gravity and an initial forward velocity.