1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
amm1812
3 years ago
10

Consider a system to be one train car moving toward another train car at rest. When the train cars collide, the two cars stick t

ogether.
What is the total momentum of the system after the collision?
800 kg • m/s
1,600 kg • m/s
2,400 kg • m/s
4,000 kg • m/s

Physics
2 answers:
sweet [91]3 years ago
5 0

Answer:

C. 2,400 kg • m/s

Explanation:

Doing it now! Good luck

oee [108]3 years ago
3 0

Answer:

Momentum after = 2400 kgm/s

Explanation:

Momentum after = momentum before

Momentum after = m1v1 +m2v2

Momentum after = (600)(4) + (400)(0)

Momentum after = 2400 kgm/s

You might be interested in
1) If a sound with the same amplitude and energy is propagated at a source, predict through which medium the sound will travel t
Lady bird [3.3K]

Answer:

denser media the speed is greater

Explanation:

The speed of sound is given by the relation

  v= \sqrt{\frac{B}{\rho} }

where B is the volume modulus and ρ the density of the medium

When analyzing the previous expression, the amplitude of the sound depends on the energy carried by the wave.

Wave speed, is given by the relationship between two magnitudes, we analyze their values ​​for different media. The volume modulus for gases has values ​​of the order of 10⁵ Pa, for liquids of the order of 10⁹ Pa and for solids of 10¹⁰ to 10¹¹ Pa, while the density has values ​​of the order of 10⁻¹ to 10⁰ kg / m³ for gases for liquids 10³ kg / m³ and for solids of the order of 10³ to 10⁴ kg / m³

 

let's find the order of magnitude of the speed of sound

Gases

     v =√ 10⁵/10⁰ = 300 m / s

liquids

     v =√ 10⁹/10³ = 1000 m / s

solid

     v = √ 10¹¹/ 10⁴ = 3000 m / s

We can see that in denser media the speed is greater

5 0
3 years ago
A fuel oil tank is an upright cylinder, buried so that its circular top is 14 feet beneath ground level. the tank has a radius o
Ierofanga [76]

Say we have a cylinder that has a height of dx, we see that the cylinder has a volume of: <span>

<span>Vcylinder = πr^2*h = π(5)^2(dx) = 25π dx

Then, the weight of oil in this cylinder is: 

Fcylinder = 50 * Vcylinder = (50)(25π dx) = 1250π dx. 

Then, since the oil x feet from the top of the tank needs to travel x feet to get the top, we have: 

Wcylinder = Force x Distance = (1250π dx)(x) = 1250π x dx. 

<span>Integrating from x1 to x2 ft gives the total work to be: (x1 = distance from top liquid level to ground level; x2 = distance from bottom liquid level to ground level)</span>

<span>W = ∫ 1250π x dx  
<span>W = 1250π ∫ x dx
W = 625π * (x2 – x1)</span></span></span></span>

<span>x2 = 14 ft  + 15 ft = 29 ft</span>

x1 = 14 ft + 1 ft = 15 ft

<span>
W = 625π * (29^2 - 15^2) 
<span>W = 385,000π ft-lbs = 1,209,513.17 ft-lbs</span></span>

3 0
4 years ago
A cube icebox of side 3cm has a thickness of 5.0cm. If 4.0 kg of ice is put in the box estimate the amount of ice remaining afte
qaws [65]

Answer:

The amount of solid ice remaining after 6 hours is approximately 3.68664 kg

Explanation:

The given parameters are;

The side length of the cube box, s = 3(0) cm = 0.3 m

The thickness of the cube box, d = 5.0 cm = 0.05 m  

The mass of ice in the box, m = 4.0 kg

The outside temperature of the cube box, T₁ = 45°C

The temperature of the melting ice inside the box, T₂ = 0°C

The latent heat of fusion of ice, L_f = 3.35 × 10⁵ J/K/hr/kg

The surface area of the box, A = 6·s² 6 × (0.3 m)² = 0.54 m²

The coefficient of thermal conductivity, K = 0.01 J/s·m⁻¹·K⁻¹

For thermal equilibrium, we have;

The heat supplied by the surrounding = The heat gained by the ice

The  heat supplied by the surrounding, Q = K·A·ΔT·t/d

Where;

ΔT = T₁ - T₂ =  45° C - 0° C = 45° C

ΔT = 45° C

Q = K·A·ΔT·t/d = 0.01 × 0.54 × 45 × 6× 60×60/0.05 = 104976

∴ The  heat supplied by the surrounding, Q = 104976 J

The heat gained by the ice = L_f × m_{melted \ ice} =3.35 × 10⁵ J/kg × m_{melted \ ice}

Therefore, from Q =  L_f × m_{melted \ ice}, we have;

Q = 104976 J =  L_f × m_{melted \ ice} = 3.35 × 10⁵ J/kg × m_{melted \ ice}

104976 J = 3.35 × 10⁵ J/kg × m_{melted \ ice}

m_{melted \ ice} = 104976 J/(3.35 × 10⁵ J/kg) ≈ 0.31336 kg

The mass of melted ice, m_{melted \ ice} ≈ 0.31336 kg

∴ The amount of solid ice remaining after 6 hours, m_{ice} = m - m_{melted \ ice}

Which gives;

m_{ice} = m - m_{melted \ ice} = 4.0 kg - 0.31336 kg ≈ 3.68664 kg

The amount of solid ice remaining after 6 hours, m_{ice} ≈ 3.68664 kg.

8 0
3 years ago
Suppose you have a glider and a hanging mass that you wish to know the masses of but you do not have a triple-beam balance avail
AlladinOne [14]

Answer:

the choice of a glider to hanging mass is a ratio of 20.2

Explanation:

The Newton´s second law for glider is:

Fnet=Ma

T=Ma

The Newton´s second law for hanging mass is:

Fnet=ma

mag-T=ma

Replacing:

mag-Ma=ma (eq. 1)

Clearing a:

a=(mg)/(m+M)

The expression for motion is:

y=vot+\frac{1}{2}at^{2}

H=0+\frac{1}{2}at^{2}

Clearing a:

a=\frac{2H}{t^{2} }

Replacing values:

a=\frac{2*0.75}{1.8^{2} } =0.46

From eq. 1:

M/m=20.2

5 0
3 years ago
You are traveling in a car toward a hill at a speed of 36.4 mph. The car's horn emits sound waves of frequency 231 Hz, which mov
Marina CMI [18]

Answer:

<em>a. The frequency with which the waves strike the hill is 242.61 Hz</em>

<em>b. The frequency of the reflected sound wave is 254.23 Hz</em>

<em>c. The beat frequency produced by the direct and reflected sound is  </em>

<em>    11.62 Hz</em>

Explanation:

Part A

The car is the source of our sound, and the frequency of the sound wave it emits is given as 231 Hz. The speed of sound given can be used to determine the other frequencies, as expressed below;

f_{1} = f[\frac{v_{s} }{v_{s} -v} ] ..............................1

where f_{1} is the frequency of the wave as it strikes the hill;

f is the frequency of the produced by the horn of the car = 231 Hz;

v_{s} is the speed of sound = 340 m/s;

v is the speed of the car = 36.4 mph

Converting the speed of the car from mph to m/s we have ;

hint (1 mile = 1609 m, 1 hr = 3600 secs)

v = 36.4 mph *\frac{1609 m}{1 mile} *\frac{1 hr}{3600 secs}

v = 16.27 m/s

Substituting into equation 1 we have

f_{1} =  231 Hz (\frac{340 m/s}{340 m/s - 16.27 m/s})

f_{1}  = 242.61 Hz.

Therefore, the frequency which the wave strikes the hill is 242.61 Hz.

Part B

At this point, the hill is the stationary point while the driver is the observer moving towards the hill that is stationary. The frequency of the sound waves reflecting the driver can be obtained using equation 2;

f_{2} = f_{1} [\frac{v_{s}+v }{v_{s} } ]

where f_{2} is the frequency of the reflected sound;

f_{1}  is the frequency which the wave strikes the hill = 242.61 Hz;

v_{s} is the speed of sound = 340 m/s;

v is the speed of the car = 16.27 m/s.

Substituting our values into equation 1 we have;

f_{2} = 242.61 Hz [\frac{340 m/s+16.27 m/s }{340 m/s } ]

f_{2}  = 254.23 Hz.

Therefore, the frequency of the reflected sound is 254.23 Hz.

Part C

The beat frequency is the change in frequency between the frequency of the direct sound  and the reflected sound. This can be obtained as follows;

Δf = f_{2} -  f_{1}  

The parameters as specified in Part A and B;

Δf = 254.23 Hz - 242.61 Hz

Δf  = 11.62 Hz

Therefore the beat frequency produced by the direct and reflected sound is 11.62 Hz

3 0
3 years ago
Other questions:
  • When the amount of a radioactive substance is reduced by 50%, what has occurred? a half-life beta radiation alpha radiation gamm
    6·2 answers
  • Which type of rock can form if extreme heat and pressure are applied to sedimentary rock?
    12·1 answer
  • Based on the typical shapes of ecg waves, which wave does this 11th cardiac cycle most resemble?
    14·1 answer
  • What is the source of all wave motion
    9·2 answers
  • Saturn has a radius of about 9.0 earth radii, and a mass 95 times the Earth’s mass. Estimate the gravitational field on the surf
    5·1 answer
  • How does The centripetal fotce change if the car has less Mass?​
    12·1 answer
  • it is determined that a certain light wave has a wavelength of 3.012x10^-12 m. the light travels at 2.99x10^8 m/s. what is the f
    9·1 answer
  • I need help please ​
    6·1 answer
  • What force does it take to accelerate a 7.2 kg object 3.0 m/s^2.
    11·1 answer
  • What condition must be satisfied for the acceleration of a falling object to be equal to the gravitational field?
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!