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amm1812
3 years ago
10

Consider a system to be one train car moving toward another train car at rest. When the train cars collide, the two cars stick t

ogether.
What is the total momentum of the system after the collision?
800 kg • m/s
1,600 kg • m/s
2,400 kg • m/s
4,000 kg • m/s

Physics
2 answers:
sweet [91]3 years ago
5 0

Answer:

C. 2,400 kg • m/s

Explanation:

Doing it now! Good luck

oee [108]3 years ago
3 0

Answer:

Momentum after = 2400 kgm/s

Explanation:

Momentum after = momentum before

Momentum after = m1v1 +m2v2

Momentum after = (600)(4) + (400)(0)

Momentum after = 2400 kgm/s

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A student swings a container of water in a vertical circle of radius 1.0 m. Calculate the minimum speed of the container so that
12345 [234]

Answer:

Explanation:

The centripetal acceleration requirement must equal gravity at the top of the circle

mg = mv²/R

  v = √Rg

  v = √(1.0(9.8))

  v = 3.1304951...

  v = 3.1 m/s

6 0
3 years ago
If you are looking up exact balues in a lookup table then it does not matter how the table is sorted
Orlov [11]
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6 0
4 years ago
14. Three identical light bulbs are connected in series, then are disconnected and arranged in parallel. For each of the scenari
Inessa [10]
In order to make things easier to describe and explain, let's call
the resistance of each bulb 'R', and the battery voltage 'V'.

a).  In series, the total resistance is 3R.
In parallel, the total resistance is R/3.
Changing from series to parallel, the total resistance of the circuit
decreases to 1/9 of its original value.

b).  In series, the total current is  V / (3R) .
In parallel, the total current is  3V / R .
Changing from series to parallel, the total current in the circuit
increases to 9 times its original value.

c).  In series, the power dissipated by the circuit is 

                                   (V) · V/3R  =  V² / 3R .

In parallel, the power dissipated by the circuit is

                                   (V) · 3V/R  =  3V² / R .

Changing from series to parallel, the power dissipated by
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8 0
3 years ago
A baseball rolls along a flat parking lot in a straight line at a constant speed of 3.8 m/s. How
Studentka2010 [4]

This is a uniform rectilinear motion (MRU) exercise.

To start solving this exercise, we obtain the following data:

<h3><u>DATA:</u></h3>
  • V = 3.8 m/s
  • D = ¿?
  • T = 15 sec

To calculate the distance, multiply the speed by the time.

We apply the following formula: d = v * t

We clear our data in the formula:

\bf{d=3.8\dfrac{m}{\not{s}}*15 \not{s} }

\bf{d=57 \ m}

The baseball in 15 seconds will roll a distance of 57 meters.

<h2>{ Pisces04 }</h2>
3 0
2 years ago
The chart shows the times and accelerations for three drivers.
aliina [53]

The lists from greatest to lowest change in velocity.Dustin → Diego → Kira. Option A is correct.

<h3 /><h3>What is acceleration?</h3>

The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

The acceleration is obtained one by one from the given data as the ratio of the velocity to the time.

For the acceleration of each, you can refer to the excel table attached below.

The velocity changes are listed from largest to least. Dustin and Diego Kira.

Hence, option A is the right answer.

To learn more about acceleration, refer to the link;

brainly.com/question/2437624

#SPJ1

6 0
2 years ago
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