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EastWind [94]
3 years ago
9

A 15 kg ball moving to the right at 2.0 m/s makes an elastic head-on collision with a 30 kg ball moving to the left at 1.5 m/s.

After the collision, the smaller ball moves to the left at 3.0 m/s. Assume that neither ball rotates before or after the collision and that both balls are moving on a frictionless surface. What is the velocity of the 30 kg ball after the collision?​
Physics
1 answer:
skad [1K]3 years ago
8 0

Answer:

1.0 ms

Explanation:

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Two cars are moving. The first car has twice the mass of the second car but only half as much kinetic energy. When both cars inc
Leno4ka [110]

Let <em>m</em> be the mass of the second car, so the first car's mass is 2<em>m</em>.

Let <em>K</em> be the kinetic energy of the second car, so the first car's kinetic energy would be <em>K</em>/2.

Let <em>u</em> and <em>v</em> be the speeds of the first car and the second car, respectively. At the start,

• the first car has kinetic energy

<em>K</em>/2 = 1/2 (2<em>m</em>) <em>u</em> ² = <em>mu</em> ²   ==>   <em>K</em> = 2<em>mu</em> ²

• the second car starts with kinetic energy

<em>K</em> = 1/2 <em>mv </em>²

It follows that

2<em>mu</em> ² = 1/2 <em>mv</em> ²

==>   4<em>u</em> ² = <em>v</em> ²

When their speeds are both increased by 2.76 m/s,

• the first car now has kinetic energy

1/2 (2<em>m</em>) (<em>u</em> + 2.76 m/s)² = <em>m</em> (<em>u</em> + 2.76 m/s)²

• the second car now has kinetic energy

1/2 <em>m</em> (<em>v</em> + 2.76 m/s)²

These two kinetic energies are equal, so

<em>m</em> (<em>u</em> + 2.76 m/s)² = 1/2 <em>m</em> (<em>v</em> + 2.76 m/s)²

==>   2 (<em>u</em> + 2.76 m/s)² = (<em>v</em> + 2.76 m/s)²

Solving the equations in bold gives <em>u</em> ≈ 1.95 m/s and <em>v</em> ≈ 3.90 m/s.

7 0
3 years ago
a plane is flying 120 m above the ground at an angle of 30 degrees to the horizontal, when the pilot released 2 fuel tanks to de
charle [14.2K]

Answer:

<u></u>

  • <u>2.26 seconds</u>
  • <u>97m/s</u>

<u></u>

Explanation:

1. Fall time

<u>i) Find the vertical speed of the plane when the tanks were released</u>

         V_{y,0}=84m/s\times sin(30\º)=42m/s

That is the same initial vertical speed of the tanks.

<u />

<u>ii) Find the fall time</u>

         y-y_0=V_{y,0}\cdot t+g\cdot t^2/2

         120=42t+4.9t^2

         

         4.9t^2+42t-120=0

         

        t=\dfrac{-42\pm\sqrt{(42)^2-4(4.9)(-120)}}{2\times 4.9}

Only the positive value has aphysical meaning: t = 2.26 seconds.

2. Speed when they hit the ground

<u>i) The horizontal speed is constant:</u>

          V_x=84m/s\times cos(30\º)\approx72.5m/s

<u />

<u>ii) The vertical speed is:</u>

            V_y=V_{y,0}+g\cdot t

            V_y=42m/s+9.8m/s^2\cdot (2.26s)\approx64.1m/s

<u>iii) Total speed</u>

          V=\sqrt{V_x^2+V_y^2}

          V=\sqrt{(72.5m/s)^2+(64.1m/s)^2}\approx97m/s

6 0
4 years ago
A large truck with a mass of 3200 kg is pulling a trailer with a mass of 2400 kg. Both are accelerating at a rate of 0.45 . Dete
Gwar [14]

Given:

Mass of truck, m1 = 3200 kg

Mass of trailer, m2 = 2400 kg

acceleration = 0.45 m/s²

Let's determine the following:

(a) The tension force between the truck and the trailer.

To find the tension between the truck and the trailer, apply the formula:

F_{\text{net}}=a(m_1+m_2)

Where:

Fnet is the tension between the truck and the trailer

a is the acceleration = 0.45 m/s²

m1 is the mass if the truck = 3200 kg

m2 is the mass of trailer = 2400 kg

Hence, we have:

\begin{gathered} F_{net}=0.45(3200+2400) \\  \\ F_{\text{net}}=0.45(5600) \\  \\ F_{\text{net}}=2520\text{ N} \end{gathered}

Therefore, the tension between the truck and the trailer is 2520N

(b) The force with which the truck is pulling.

The tension between the truck and the trailer is equivalent to the force on the trailer.

thus, we have:

\begin{gathered} T=m_2a \\  \\ T=2400\times0.45 \\  \\ T=1080\text{ N} \end{gathered}

Therefore, the force with which the truck is pulling is 1080N.

ANSWER:

(a) 2520N

(b) 1080 N

8 0
2 years ago
Which is correct? 1.00 m = 100. dam 1.00 m = 100. dm 1.00 m = 100. cm 1.00 m = 100. mm
weqwewe [10]

Answer:

1.00 m = 100. cm

Explanation:

1m=0.1dam

1m=100cm

1m=1000mm

8 0
3 years ago
Read 2 more answers
9. A body is a particular amount of matter. It can be a solid, liquid or gas. It can be
soldier1979 [14.2K]

Answer:

B. Time and Space

Explanation:

Matter is a pshyical or corporeal susbtance in general, whether solid, liquid, or gaseous especially as distinguised from incorpeal substance, as spirit or mind, or form qualities, actions, and the

Within this time-and-space boundary, all matter exists. All matter is made up of atoms. Because these atoms take up space in the universe, solids, liquids, and gases are recognized as existing and may be found in all three dimensions.

Time is a figurative term. Space has three dimensions but time only has one.

7 0
2 years ago
Read 2 more answers
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