Answer:
First one is voltage
second is resistance
third is electric current
hope this helped!!
Answer:
Explanation:
In a L C R circuit, the average power is given by

As given in the question
CosФ = R / Z
And we know that

So


Answer:
x sin nx = x cos nx
same as
theta / theta x (xsin (nx)) = sin (nx) + (nx) cos (nx)
1 horsepower is equal to 746 W, so the power of the engine is

The power is also defined as the energy E per unit of time t:

Where the energy corresponds to the work done by the engine, which is

. Re-arranging the formula, we can calculate the time t needed to do this amount of work:
<span> the tangent function of 2mi/5mi = 21.8 degrees
cosine of that angle = cos (21.8 degrees)
=0.928
multiply 0.928 with 570 = 570*0.928
Closing velocity = 529.23 mph
</span><span>As the plane gets closer to radar station, tangent function becomes infinity and the cosine function becomes zero.....
</span>0*570 = 0