A 15 kg ball moving to the right at 2.0 m/s makes an elastic head-on collision with a 30 kg ball moving to the left at 1.5 m/s.
1 answer:
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Answer:
Explanation:
These Hooke's Law problems are tricky. Here's what we need to know that clears up the problem entirely. The final and also the max speed of the block will be reached at the point where the potential energy of the system is 0. So the equation we need, namely,
can be simplified down to
and we solve this first for KE:
and, paying NO attention whatsoever to significant digits here (because if you did the answer you get is not one of the choices)
KE = 3.825 J. Now we can use that value of kinetic energy and solve for the speed we need:
so
so
so
v = 3.91 m/s
Answer:
Part a)
Part b)
Part c)
Part d)
Explanation:
Part a)
As we know that speed of package is same as that of helicopter in horizontal direction
So after time "t" the velocity in x direction will remain constant while in Y direction it will go free fall
So we have
Part b)
Distance from helicopter is same as the distance of free fall
so we will have
Part c)
If helicopter is rising upwards with uniform speed
then final speed of the package after time t is given as
Part d)
distance from helicopter
Answer:
Explanation:
Given that:
- mass of plank,
- length of plank,
From the image we can visualize the given situation.
Consider the given plank to be mass-less and having a uniformly distributed mass of 1.5 kg per meter.
<u>Now in the balanced condition:</u>
.......................(1)
...........................(2)
is the force acted by the tailgate on the plank.
<u>Substitute the value from (2) into (1):</u>
is the force acted by the wall upon the plank.
