Here if we assume that there is no air friction on both balls then we can say
now the acceleration is given as
so here both the balls will have same acceleration irrespective of size and mass
so we can say that to find out the time of fall of ball we can use
now from above equation we can say that time taken to hit the ground will be same for both balls and it is irrespective of its mass and size
Answer:
The final equilibrium temperature of the system is
For the ice it would melt completely the mass that would remain is Zero
Explanation:
In the following question we are provided with
Mass of the ice = 129 g = 0.129 kg
Mass of the steam = 19 g = 0.019 kg
Initial temperature is = 0°C
Temperature of steam = 100°C
Following the change of state of water in the question
The energy required by ice to change to water is mathematically given as
Where is a constant known as heat of fusion and the value is
The energy been released when the steam changes to water is mathematically given as
Where is a constant known as heat of vaporization and the value is
The energy released when the temperature of water decrease from 100°C to 0°C is
100°C)
Where is the specific heat of water which has a value
Looking at the values we obtained we noticed that ]
What this means is that the ice will melt
bearing in mind the conservation of energy
looking the way at which water at different temperature were mixed according to the question
Heat lossed by the vapor = heat gained by ice
Answer:
Explanation:
The root mean square velocity of the gas at an equilibrium temperature is given by the following formula:
where,
v = root mean square velocity of molecules:
R = Universal Gas Constant
T = Equilibrium Temperature
M = Molecular Mass of the Gas
Therefore,
For T = T₁ :
For T = T₂ :
Since both speeds are given to be equal. Therefore, comparing both equations, we get: