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jeka94
1 year ago
10

A non-rigid balloon is held in a chamber set at 293 K and 1 atm of pressure. The balloon's volume is 0.05 m³. If the pressure in

the room is increased to 5
atm, what is the new volume of the balloon?
Physics
1 answer:
enyata [817]1 year ago
5 0

A non-rigid balloon is held in a chamber set at 293 K and 1 atm of pressure. The balloon's volume is 0.05 m³. If the pressure in the room is increased to 5 atm, then the new volume of the balloon would be 0.01 meter³

<h3>What is an ideal gas?</h3>

It is an imaginary gas for which the volume occupies by it is negligible, this gas does not exist in a practical situation and the concept of an ideal gas is only the theoretical one, the real gases approach the behaviors of an ideal gas at a very high temperature and very low pressure.

By using Boyle's law

P₁V₁=P₂V₂

Where P₁, and V₁, are initial pressure and  volume

and P₂ and  V₂, are the final pressure and volume

By substituting the values in the above equation

P₁ = 1 atm

V₁= 0.05 meter³

P₂ = 5.0 atm

V₂= ? meter³

The only unknown term which we have to find is the final volume of the balloon

1.0 ×0.05=5.0×V₂

V₂ =0.01 meter³

Thus, the new volume of the balloon would be 0.01 meter³

Learn more about ideal gas from here

brainly.com/question/8711877

#SPJ1

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Use Hooke's Law to determine the work done by the variable force in the spring problem. Nine joules of work is required to stret
natima [27]

Answer:

29.16 J

Explanation:

From Hook's law,

W = 1/2(ke²)..................... Equation 1

Where W = work done, k = Spring constant, e = extension.

Given: W = 9 J, e = 0.5 m.

Substitute into equation 1

9 = 1/2(k×0.5²)

Solve for k

k = 18/0.5²

k = 72 N/m.

The work done required to stretch the spring by additional 0.4 m is

W = 1/2(72)(0.4+0.5)²

W = 36(0.9²)

W = 29.16 J.

6 0
3 years ago
A bowler throws a bowling ball of radius R = 11 cm down the lane with initial speed v₀ = 7.5 m/s. The ball is thrown in such a w
salantis [7]

Answer:

a) t = 0.74s

b) D = 4.76m

c) Vf = 5.35m/s

Explanation:

The ball starts rolling when Vf = ωf*R.

We know that:

Vf = Vo - a*t

ωf = ωo + α*t

With a sum of forces on the ball:

Ff = m*a

\mu*N = m*a

\mu*m*g = m*a

a=\mu*g=2.9m/s^2

With a sum of torque on the ball:

Ff*R = I*\alpha

\mu*m*g*R = 2/5*m*R^2*\alpha

\alpha=5/2*\mu*g/R=65.9rad/s^2

Replacing both accelerations:

Vo - a*t=\alpha*t*R

7.5 - 2.9*t=65.9*t*0.11

t=0.74s

The distance will be:

D = Vo*t-1/2*a*t^2

D = 4.76m

Final velocity:

Vf=Vo-a*t

Vf=5.35m/s

7 0
3 years ago
If a point has 40 J of energy and the electric potential is 8 V, what must be the charge?
Alekssandra [29.7K]

If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C

<u>Given the following the details;</u>

  • Energy = 40 Joules
  • Electric potential = 8 Volts

To find the quantity of charge;

Mathematically, the quantity of charge with respect to electric potential is given by the formula;

Quantity \; of \; charge = \frac{Energy}{Electric \; potential}

Substituting the values into the formula, we have;

Quantity \; of \; charge = \frac{40}{8}

<em>Quantity of charge = 5 Coulombs</em>

Therefore, the quantity of charge must be <em>5 Coulombs.</em>

Find more information: brainly.com/question/21808222

8 0
3 years ago
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Why is the unit of momentum called derived unit​
Mnenie [13.5K]

Answer:

the SI unit of momentum is :- kg.ms-1

and we know that,

kinetic energy = 1/2 mv2

E=p2/2m

p=(2Em)1/2

so the derived units are (J.kg)1/2

Explanation:

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Ahat [919]

Answer:

its how life meets water and earth meets air.

Explanation:

4 0
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