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storchak [24]
2 years ago
15

Can someone please help me?

Mathematics
1 answer:
lawyer [7]2 years ago
3 0
Area is 140 and perimeter is 16
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Rewrite the following integral in spherical coordinates.​
lora16 [44]

In cylindrical coordinates, we have r^2=x^2+y^2, so that

z = \pm \sqrt{2-r^2} = \pm \sqrt{2-x^2-y^2}

correspond to the upper and lower halves of a sphere with radius \sqrt2. In spherical coordinates, this sphere is \rho=\sqrt2.

1 \le r \le \sqrt2 means our region is between two cylinders with radius 1 and \sqrt2. In spherical coordinates, the inner cylinder has equation

x^2+y^2 = 1 \implies \rho^2\cos^2(\theta) \sin^2(\phi) + \rho^2\sin^2(\theta) \sin^2(\phi) = \rho^2 \sin^2(\phi) = 1 \\\\ \implies \rho^2 = \csc^2(\phi) \\\\ \implies \rho = \csc(\phi)

This cylinder meets the sphere when

x^2 + y^2 + z^2 = 1 + z^2 = 2 \implies z^2 = 1 \\\\ \implies \rho^2 \cos^2(\phi) = 1 \\\\ \implies \rho^2 = \sec^2(\phi) \\\\ \implies \rho = \sec(\phi)

which occurs at

\csc(\phi) = \sec(\phi) \implies \tan(\phi) = 1 \implies \phi = \dfrac\pi4+n\pi

where n\in\Bbb Z. Then \frac\pi4\le\phi\le\frac{3\pi}4.

The volume element transforms to

dx\,dy\,dz = r\,dr\,d\theta\,dz = \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi

Putting everything together, we have

\displaystyle \int_0^{2\pi} \int_1^{\sqrt2} \int_{-\sqrt{2-r^2}}^{\sqrt{2-r^2}} r \, dz \, dr \, d\theta = \boxed{\int_0^{2\pi} \int_{\pi/4}^{3\pi/4} \int_{\csc(\phi)}^{\sqrt2} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta} = \frac{4\pi}3

4 0
2 years ago
Write each number as a fraction or Mixed number.<br> (Please help! I'm trying to promote!)
aivan3 [116]

Answer:

0.7 repeating is 7/9

0.04 repeating is 4/99

4.45 repeating 4 4/11

2.19191919...... is 2 19/99

hope this helps

have a good day :)

Step-by-step explanation:

6 0
2 years ago
The perimeter of a rectangle is 84 inches. The width of the rectangle is 12 inches. What is the length of the rectangle?
german
The length of the rectangle is 30
5 0
1 year ago
What are the solutions of the equation (x-3)^2 + 2(x-3) -8 = 0
Mariulka [41]
Expand and simplify
(x-3) (x-3) +2(x-3) -8=0
(x-3+2)(x-3)-8=0
(x-1)(x-3)-8=0
x^2 -4x +3-8=0
x^2 - 4x -5=0
x^2 -5x +x-5=0
x(x-5)+x-5=0
(x+1)(x-5)=0
x= - 1, 5
6 0
3 years ago
Read 2 more answers
What expression represents '' five times the quotient of some number and ten"? A.5(z/10) B.5(z-10) C.5(10/z) D.5(10-z)
maw [93]

Answer:

Option A is correct

5(\frac{z}{10})

Step-by-step explanation:

Let the number be z.

Given the statement:

'' five times the quotient of some number and ten"

" quotient of some number and ten" translated to \frac{z}{10}

"five times the quotient of some number and ten" translated to 5 \times \frac{z}{10}

Then, the expression we get,

5(\frac{z}{10})

Therefore, 5(\frac{z}{10}) expression represents '' five times the quotient of some number and ten"

5 0
2 years ago
Read 2 more answers
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