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Paraphin [41]
3 years ago
11

What is the force exerted on an object if it experiences 1000 Pa of pressure over an area of 25 m2? NO UNIT, NO COMMA, AND NO DE

CIMAL
Biology
1 answer:
rodikova [14]3 years ago
6 0

Answer:

F = 25000 N

Explanation:

It is given that,

Pressure exerted by the object, P = 1000 Pa

Area of cross section, A = 25 m²

We need to find the force exerted on an object. The pressure exerted by an object is equal to the force acting per unit area. So,

P=\dfrac{F}{A}\\\\F=P\times A\\\\F=1000\ Pa\times 25\ m^2\\\\F=25000\ N

So, the force exerted on an object is 25000 N.

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<em>p =-3/2p</em>

<h3><u>Solution;</u></h3>

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<em> Therefore; 2p = -3q</em>

<em>   hence;  p = -3/2q. </em>


<h3>2. <u>Answers</u>;</h3>

<em>b = 19/2</em>

<h3><u>Solution;</u></h3>

To solve for b when the value of a = 3

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<em>12 = 2b -7</em>

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<em>19 = 2b</em>

<em>b = 19/2</em>


<h3>3. <u>Answer;</u></h3>

<em>r =d/t</em>

<h3><u><em>Solution;</em></u></h3>

To solve for r 

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In order to get r, we divide both sides by t

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<h3>4. <u>Answer;</u></h3>

<em>Width = 30 units</em>

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The width of a rectangle with a given perimeter of 90 and length is 15.

The perimeter of a rectangle is given by;

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<em>Subtracting from both sides;</em>

<em>W = 45 -15 </em>

<em>W = 30 </em>

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