Answer:
The correct option is: B. 13g
Explanation:
Given: Molar mass of iron (II) sulfate: m = 260g/mol,
Molarity of iron (II) sulfate solution: M = 0.1 M,
Volume of iron (II) sulfate solution: V = 500 mL = 500 × 10⁻³ = 0.5 L (∵ 1L = 1000mL)
Mass of iron (II) sulfate taken: w = ? g
<em>Molarity</em>:
Here, n- total number of moles of solute, w - given mass of solute, m- molar mass of solute, V- total volume of solution in L
∴ <em>Molarity of iron (II) sulfate solution:</em>
⇒
⇒
⇒ <em>mass of iron (II) sulfate taken:</em>
<u>Therefore, the mass of iron (II) sulfate taken for preparing the given solution is 13 g.</u>
It is c I hope I helped out with this question!.
<h3>Answer:</h3>
53 fahrenheit
<h3>Explanation:</h3>
Temperature is a measure of thermal energy. It goes down when thermal energy decreases. Of your choices, the temperature lower than 62 °F is 53 °F.
<h3>
Answer:</h3><h3>a) 9.033 × 10²³ particles</h3><h3>b) 4.068 × 10²⁴ particles</h3><h3>c) 1.51 × 10²³ particles</h3>
Explanation:
For us to answer these questions, we have to know two formulas:
- Number of particles = moles × Avogadro's Number
- Moles = Mass ÷ Molar Mass
Therefore:
a) particles of Na = 1.50 mol × (6.022 × 10²³) particles/mol
= 9.033 × 10²³ particles
b) particles of Pb = 6.755 mol × (6.022 × 10²³) particles/mol
= 4.068 × 10²⁴ particles
c) particles of Si
= (7.02 g ÷ 28.085 g/mol) × (6.022 × 10²³) particles/mol
= 1.51 × 10²³ particles
<span>using the law pv=nrT and equating these you get the equation v1/t1 = v2/t2 since pressure is constant it also cancels with n and r. show that v1=36.4, t1 = 25 + 273.15 and t2 = 88 +273.15. 273.15 is the Kelvin conversion. then solve for v2. This is 44.1 L.</span>