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4 years ago

How many valence electrons does the Lewis structure for a chlorine atom show

Chemistry

2 answers:

Marianna [84]4 years ago

8 0

7 valance electrons the Lewis structure for a chlorine atom show.

Explanation:

Lewis structure is used to keep track of the valance electrons of each atom and share them in bonding. Every valance electron is represented as a dot around the element to keep their count.

Paired VE’s are shown as ‘:’ and unpaired as ‘.’ in the representation. A chlorine Cl atom has 17 electrons. & of them are valance electrons. Out of the seven six are paired electrons and one is unpaired.

ohaa [14]4 years ago

6 0

Answer: D

Explanation:

Chlorine is in group 7 or (VII) in Roman numerals, which means it has 7 balance electrons. It only needs one electron to become stable, hence it is next to the noble gases

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3 years ago

For which of the following elements would the most common ion be expected to have a larger radius than that of its corresponding

Andre45 [30]

Answer: The ion that is expected to have a larger radius than the corresponding atom is chlorine.

Explanation:

There are two types of ions:

Cations: They are formed when an atom looses its valence electrons. They are positive ions.
Anions: They are formed when an atom gain electrons in its outermost shell. They are negative ions.

For positive ions, the removal of electron increases the nuclear charge for an outermost electron because the outermost electrons are more strongly attracted by the nucleus. So, the effective nuclear charge increases for cations and thus, the size of the cation will be smaller than that of the corresponding atom.

For negative ions, the addition of electron decreases the nuclear charge for an outermost electron because the outermost electrons are less strongly attracted by the nucleus. So, the effective nuclear charge decreases for anions and thus, the size of the anion will be larger than that of the corresponding atom.

For the given options:

Option a: Chlorine

Chlorine gains 1 electron and form $Cl^-$ ion

Option b: Sodium

Sodium looses 1 electron and form $Na^+$ ion

Option c: Copper

Copper looses 2 electrons and form $Cu^{2+}$ ion

Option d: Strontium

Strontium looses 2 electrons and form $Sr^{2+}$ ion

Hence, the ion that is expected to have a larger radius than the corresponding atom is chlorine.

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3 years ago

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Answer:

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Explanation:

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