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ioda
3 years ago
8

Find a right triangle that has legs with your irrational Lengths and a hypotenuse with a rational Length

Mathematics
1 answer:
cluponka [151]3 years ago
4 0

gg easy


the legs of a triangle are related as a^2+b^2=c^2 wehre a, b, and c are the legs and the hypotonuse of a triangle respectively


let's find some stuff

one easy way is to find a rational value for c find values of a and b

lets pick c=5

a^2+b^2=5^2

a^2+b^2=25

now split up 25 into 2 things that don't have rational square roots

if we say a^2=19 and b^2=6 then we get

a=\sqrt{19} and b=\sqrt{6} (which are both irrational)

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5 0
3 years ago
What is 0.2(5x – 0.3) – 0.5(–1.1x + 4.2) simplified? 0.2 [5x + (–0.3)] + (–0.5)(–1.1x + 4.2) x – 2.16
dedylja [7]

0.2(5x – 0.3) – 0.5(–1.1x + 4.2) = 6.5x – 2.06

Solution:

Given expression is 0.2(5x – 0.3) – 0.5(–1.1x + 4.2).

To simplify the expression, first multiply the common term within the bracket.

0.2(5x – 0.3) – 0.5(–1.1x + 4.2)

            = (5x × 0.2 – 0.3 × 0.2)  + (–1.1x × (–0.5) + 4.2 × (–0.5))

            = (1x – 0.06) + (5.5x – 2.1)

            = x – 0.06 + 5.5x – 2

Combine like terms together.

            = x + 5.5x – 0.06 – 2

            = 6.5x – 2.06

0.2(5x – 0.3) – 0.5(–1.1x + 4.2) = 6.5x – 2.06

Hence the simplified form of 0.2(5x – 0.3) – 0.5(–1.1x + 4.2) is 6.5x – 2.06.

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3 years ago
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