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3 years ago

5

Phenylketonuria (pku) is an inherited disease caused by an autsomal recessive allele. if two individuals who are carriers of pku

have two children, what is the probability that neither child will have pku? give your answer as a fraction or a decimal.

1 answer:

velikii [3]3 years ago

3 0

It's 25 percent as it's Aa plus Bb which gives 4 combinations and one of them is the answer. thus 1/4 equals 25percent

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3 years ago

Here is data on the flow of students through a school.70% of freshmen pass and become sophomores, 20% fail and repeat as freshme

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Answer:

(a) 0.367

(b) 0.544

(c) 0.616

(d) 0.792

(e) 1.087

Step-by-step explanation:

The transition matrix T multiplying the vector ...

{freshmen, sophomores, juniors, seniors, graduates, dropouts}

can be written as

$T=\left[\begin{array}{cccccc}0.2&0&0&0&0&0\\0.7&0.1&0&0&0&0\\0&0.8&0.1&0&0&0\\0&0&0.8&0.08&0&0\\0&0&0&0.82&1&0\\0.1&0.1&0.1&0.1&0&1\end{array}\right]$

(a) Then the 4th power of this matrix (1st attachment) will tell the number of freshmen graduating in 4 years. That will be ...

$(T^4)_{5,1}=0.367360\approx 0.367$

__

(b) Then the 5th power of this matrix (2nd attachment) will tell the number of freshmen graduating in 5 years. That will be ...

$(T^5)_{5,1}=0.543693\approx 0.544$

__

(c) The Nth power of matrix T as N approaches infinity (3rd attachment) will tell the numbers of students of each class who eventually graduate. For freshmen, that fraction is ...

$(T^{\infty})_{5,1}=0.616210\approx 0.616$

__

(d) As in part (c), the desired fraction is ...

$(T^{\infty})_{5,3}=0.792271\approx 0.792$

__

(e) The expected number of years spent in school is the sum of the products of time in school and the probability of taking that time. The expected value in years is ...

$\sum\limits_{k=1}^{\infty}{k\cdot 0.92\cdot0.08^{k-1}}=\dfrac{0.92}{(1-0.08)^2}=\dfrac{1}{0.92}\approx 1.087$

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