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Veronika [31]
3 years ago
8

A recent poll of over 2,000 adults was designed to answer the question "Are adults superstitious?" One survey item concerned the

phrase "see a penny, pick it up, all day long you'll have good luck." The poll found that just one-third of adults (33%) believe finding and picking up a penny is good luck. Consider a random sample of 15 adults and let x represent the number who believe finding and picking up a penny is good luck. Complete parts a though f below.A. A success is an adult who does not believe finding and picking up a penny is good luckB. A success is an adult who believes finding and picking up a penny is bad luck.C. A success is an adult who does not believe finding and picking up a penny is bad luck.D. A success is an adult who believes finding and picking up a penny is good luck.
Mathematics
1 answer:
RSB [31]3 years ago
8 0

Answer:

i think you can divide 2,000 and 30 it might get you the answers if not try these adding multiplucation or subtraction.

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x=-3

Step-by-step explanation:

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2 years ago
Of 150 adults selected randomly from one town, 30 of them smoke. Construct a 99% confidence interval for the true percentage of
anyanavicka [17]

Answer:

The 99% confidence interval for the true percentage of all adults in the town that smoke is (0.1159, 0.2841).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

Of 150 adults selected randomly from one town, 30 of them smoke. This means that n = 150, p = \frac{30}{150} = 0.2

99% confidence interval

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.20 - 2.575\sqrt{\frac{0.20*0.80}{150}} = 0.1159

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.20 + 2.575\sqrt{\frac{0.20*0.80}{150}}{119}} = 0.2841

The 99% confidence interval for the true percentage of all adults in the town that smoke is (0.1159, 0.2841).

3 0
3 years ago
Please please help me
miskamm [114]

Answer:

41

3 {x}^{2}  - 2x + 1

now \:  \: x = 4

3 {(4)}^{2}  - 2(4) + 1

3(16) - 8 + 1

48 - 8 + 1 = 41

41 is the answer

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