Addshow all steps please

Mathematics

1 answer:

choli [55]3 years ago

3 0

$\bf \cfrac{3}{x-2}+\cfrac{4}{x-1}-\cfrac{1}{x}$ so, no breaks on the denominator thus, the LCD will be all three then.

$\bf \cfrac{3}{x-2}+\cfrac{4}{x-1}-\cfrac{1}{x}\implies \cfrac{[3x(x-1)]+[4x(x-2)]-[(x-2)(x-1)]}{x(x-2)(x-1)}
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\cfrac{[3x^2-3x]+[4x^2-8x]-[x^2-3x+2]}{x(x-2)(x-1)}
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\cfrac{3x^2-3x+4x^2-8x-x^2+3x-2}{x(x-2)(x-1)}
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\cfrac{6x^2-8x-2}{x(x-2)(x-1)}\implies \cfrac{2(x^2-4x-1)}{x(x-2)(x-1)}$

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Given: △ABC, m∠C=90° m∠ABC=30°, AL ∠ bisector CL=6 ft. Find: LB

vlada-n [284]

For a better understanding of the solution given here please go through the diagram in the file attached.

To solve this question we will make use of the "Triangle Angle Bisector Theorem", which states that, "An angle bisector of an angle of a triangle divides the opposite side in two segments that are proportional to the other two sides of the triangle."

Thus, in our question, we will have:

$\frac{LB}{CL}= \frac{AB}{AC}$