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Mamont248 [21]
3 years ago
8

To the nearest hundred, what is the greatest whole number that rounds to 2,500 to the least who.e number?

Mathematics
2 answers:
julsineya [31]3 years ago
5 0

Answer: 2,400

Step-by-step explanation: You're rounding  2,500 to the nearest least whole hundred  number, so that would be 2,400 I hope I explained that right...

Varvara68 [4.7K]3 years ago
4 0

Answer:

2400

Step-by-step explanation:

Plz do brainliess  answer

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Is 60.43 an irrational number
zhuklara [117]

Answer:

No, It is rational

Step-by-step explanation:

An number with a finite number of decimal point/numbers can be rational unlike numbers that repeat on forever like the number pi

4 0
2 years ago
Help please i need answer ASAP
Juli2301 [7.4K]

If the result is reflected over x-axis and vertically stretched by a factor of 5, the result will be g(x) = -5(x - 1)²

<h3>Transformation of functions</h3>

Transformation is a way of changing the position of an object o the xy plane. Given the parent function expressed as

f(x) = x^2

If the function is shifted to the left by unit, then we will have h(x) = (x - 1)²

If the result is reflected over x-axis and vertically stretched by a factor of 5, the result will be g(x) = -5(x - 1)²

Learn more on translation here: brainly.com/question/12861087

#SPJ1

8 0
1 year ago
In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa
Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

^nC_r=\dfrac{n!}{r!(n-r)!}

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434

Hence, the required number of ways =27434

5 0
3 years ago
3x exponent 2=48 solve the equation please
Sever21 [200]

Answer:

x = 4,-4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
2 over 3 divided by 5
Yuliya22 [10]
2/3 divide by 5 is 2/15

Remember keep change flip

2/3 times 1/5 is 2/15

Hope this helps!
6 0
3 years ago
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