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Ainat [17]
3 years ago
15

we have 4 1/2 cups of chocolate chips. a batch of our madison cookies requires 3/4 cup of chocolate chips. how many batches can

we make?
Mathematics
1 answer:
My name is Ann [436]3 years ago
7 0

Answer:

You can make 6 batches of cookies.

Step-by-step explanation:

3/4 + 3/4 = 1 1/2 (2)

1 1/2 + 1 1/2 = 3 (4)

3 + 1 1/2 = 4 1/2 (6)

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Please simplify this ITS URGENT !!
frutty [35]

Answer:

5 {x}^{2}  - 4x -  3

Step-by-step explanation:

(8 {x}^{2}  - 5x + 1) - (3 {x}^{2}  - x + 4) \\  = 8 {x}^{2}  - 5x + 1 -  3{x}^{2}  + x - 4 \\  = 5 {x}^{2}  - 4x - 3

5 0
3 years ago
A block of concrete is 1m long, 50cm wild and 4cm thick. 1.calculate the volume of the block in cm3 .2.if 1cm has a mass of 2.7g
Nonamiya [84]

9514 1404 393

Answer:

  • 20,000 cm³
  • 54 kg

Step-by-step explanation:

1 m is 100 cm, so the volume is ...

  V = LWH

  V = (100 cm)(50 cm)(4 cm) = 20,000 cm³ . . . volume

__

The mass is ...

  (20,000 cm³)(2.7 g/cm³) = 54,000 g = 54 kg

The mass of the block is 54 kg.

7 0
3 years ago
Express the ratio AC/DF in simplest form
murzikaleks [220]

Answer:

\frac{n}{28 \: cm}

Step-by-step explanation:

AC = n, DF = 28 cm

\huge \red{ \frac{AC}{DF} }=  \purple{ \frac{n}{28 \: cm}}  \\

5 0
3 years ago
The time needed to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes
Komok [63]

Answer:

a. The probability of completing the exam in one hour or less is 0.0783

b. The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. The number of students will be unable to complete the exam in the allotted time is 8

Step-by-step explanation:

a. According to the given we have the following:

The time for completing the final exam in a particular college is distributed normally with mean (μ) is 77 minutes and standard deviation (σ) is 12 minutes

Hence, For X = 60, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=60−77 /12

Z=−1.4167

Using the standard normal table, the probability P(Z≤−1.4167) is approximately 0.0783.

P(Z≤−1.4167)=0.0783

Therefore, The probability of completing the exam in one hour or less is 0.0783.

b. In this case For X = 75, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=75−77 /12

Z=−0.1667

Using the standard normal table, the probability P(Z≤−0.1667) is approximately 0.4338.

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is obtained as follows:

P(60<X<75)=P(Z≤−0.1667)−P(Z≤−1.4167)

=0.4338−0.0783

=0.3555

​

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. In order to compute  how many students you expect will be unable to complete the exam in the allotted time we have to first compute the Z−score of the critical value (X=90) as follows:

Z=  X−μ /σ

Z=90−77 /12

Z​=1.0833

UsING the standard normal table, the probability P(Z≤1.0833) is approximately 0.8599.

Therefore P(Z>1.0833)=1−P(Z≤1.0833)

=1−0.8599

=0.1401

​

Therefore, The number of students will be unable to complete the exam in the allotted time is= 60×0.1401=8.406

The number of students will be unable to complete the exam in the allotted time is 8

6 0
3 years ago
What is the slope of the line shown in the graph?
faust18 [17]

Answer:

-1 over 2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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