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3 years ago

15

we have 4 1/2 cups of chocolate chips. a batch of our madison cookies requires 3/4 cup of chocolate chips. how many batches can

we make?

1 answer:

My name is Ann [436]3 years ago

7 0

Answer:

You can make 6 batches of cookies.

Step-by-step explanation:

3/4 + 3/4 = 1 1/2 (2)

1 1/2 + 1 1/2 = 3 (4)

3 + 1 1/2 = 4 1/2 (6)

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rosijanka [135]

19. -4x(3x-5y)

20. 6x+ 20

21. $\frac{a+1}{2a}$

22. $\frac{5x-23}{4}$

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2 years ago

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Using proportional reasoning, about how many of 180 seventh grade students in school would like to snorkel

amm1812

Answer:

We need some aditional data. For example, the average number of students who like to snorkel in certain population.

Step-by-step explanation:

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3 years ago

Find the length of a diagonal of a square with sides 10in. long

Ghella [55]

Hey!!!
Answer is....
diagonals of square bisect each other at right angles.
let diagonal be 2x
Using Pythagoras in a triangle enclosed by a side and 2 half diagonals...
${x}^{2} + {x}^{2} = {10}^{2}$
$2 {x}^{2} = 100$
${x }^{2} = 50$
$x = \sqrt{50}$
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cm......

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3 0

3 years ago

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A set of magical wand prices are normally distributed with a mean of 50 dollars and a standard deviation of 4 dollars. A blackth

Anna11 [10]

Complete Question

A set of magical wand prices are normally distributed with a mean of 50 dollars and a standard deviation of 4 dollars. A blackthorn wand has a price of 45.20. What proportion of wand prices are lower than the price of the blackthorn wand? You may round your answer to four decimal places

Answer:

0.1151

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = $45.20

μ is the population mean = $50

σ is the population standard deviation = $4

We are solving for x < 45.20

Hence:

z = 45.20 - 50/4

z = -1.2

Probability value from Z-Table:

P(x<45.20) = 0.11507

Approximately to 4 decimal places = 0.1151

Therefore, the proportion of wand prices that are lower than the price of the blackthorn wand is 0.1151

8 0

3 years ago

For what value of k will these pairs of simultaneous equations have no solution?

yKpoI14uk [10]

Kx-3y=k
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x= $\frac{k+3}{k-12}$
Also y= $\frac{5k}{k-12}$
We can not divide with zero.
k-12=0
k=12
For k= 12 equations have no solutions.

4 0

3 years ago