If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18.
<h3>What is an ideal gas equation?</h3>
The ideal gas equation is given below.

The equation can be written as

Where M is the molar mass, P is the pressure, V is the volume, R is the universal gas constant, T is the temperature, and m is the mass of the gas.
Then the molar mass of a 0.622-gram sample of gas has a volume of 2.4 L at 287 K and 0.850 atm.
V = 2.4 L = 0.0024
P = 0.85 atm = 86126.25 Pa
T = 287 K
m = 0.622
R = 8.314
Then we have

Then the molar mass of the gas is 7.18.
More about the ideal gas equation link is given below.
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Answer:
Step-by-step explanation:
Thrice the sum of three fifths and two thirds less one half is expressed as 3(3/5 + 2/3)-1/2
Open the parenthesis
3(3/5) + 3(2/3) - 1/2
= 9/5 + 6/3 - 1/2
Find LCM
= 9(6)+10(6)-15/30
= 54+60-15/30
= 54+45/30
= 99/30
= 3 9/30
= 3 3/10
Hence the number id 3 3/10
Answer:
12.8 so answer 12 or 13
Step-by-step explanation:
15÷5/8= 12.8
1.5. if you divide the denominator by the numerator you will get your decimal.
Answer:
$614.63
Step-by-step explanation:
you would multiple 16.50 by 37.25 and the answer comes to 614.625 you would round up to $614.63