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mrs_skeptik [129]

2 years ago

9

Find the additive inverse of each number. 1. 15 2. – 27 3. 7 9 4. 9 16  5. 0 6. – 1

1 answer:

nasty-shy [4]2 years ago

4 0

The additive inverse of a number is otherwise known as its opposite.

The additive inverse of 15 is -15.
The additive inverse of -27 is 27.
The additive inverse of 0 is 0 itself!

a + (-a) = 0
A number plus its additive inverse equals zero!

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What is equivalent to (4xy-3z)^2 and<br> what type of special product is it?

sergey [27]

Answer:

the answer on edgenuty is option D

Step-by-step explanation:

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3 years ago

Find the length x to the nearest whole number. A right triangle has a vertical leg of length x units, a base leg with a length o

wel

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value of x is $x = 274 \ unites$

Step-by-step explanation:

From the question we are told that

The length of the vertical length is $x$

The length of the base leg is L = 330 + d units

The length of the bisecting line segment is h

The base angle is $\theta = 28^o$

The angle between d and line segment is $\theta_1 = 56^o$

For the first angle

$Tan \theta_1 = \frac{x}{d}$

=> $d = \frac{x}{Tan \theta _1}$

For the whole big triangle

$Tan \theta = \frac{x}{330 + d}$

=> $d = \frac{x}{Tan \theta } -330$

So equating the both d

$\frac{x}{Tan \theta _1} = \frac{x}{Tan \theta } -330$

Substitute values

$\frac{x}{Tan (56)} = \frac{x}{Tan (28) } -330$

$0.6745 x = 1.880x -330$

$1.20549 x = 330$

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5 0

2 years ago

Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

2 years ago

Solve using elimination.<br> 2x – 3y = -7<br> -8x + 3y = 19

Brums [2.3K]

Answer:

-2,1

Step-by-step explanation:

5 0

3 years ago

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kari74 [83]

Answer:

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Step-by-step explanation:

Let the amount of cheese required by the recipe be "x"

Ann increased 60% from original amount and then used up 80 grams. Thus:

<em>Original, increased by 60%, became 80</em>

<em />

This translated to algebraic equation would be:

x + 0.6x = 80

<u>Note:</u> 60% = 60/100 = 0.6

So we can solve the above equation for "x" and get our answer. Shown below:

$x + 0.6x = 80\\1.6x=80\\x=\frac{80}{1.6}\\x=50$

Hence,

the recipe required 50 grams of cheese

6 0

2 years ago