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oee [108]
3 years ago
12

If you join all the vertices of a heptagon how many quadrilaterals will you have

Mathematics
1 answer:
dem82 [27]3 years ago
5 0
When you join all the vertices, you can get 35 quadrilaterals.
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Please helppp due in 10 minutesss!!!
Blizzard [7]

Answer:

Step-by-step explanation:

A=3

B=4

C=6

D=5

E=1

F=7

G=2

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3 years ago
What's the awnser to the one about Isabella
Irina18 [472]
I cant even see the picture clearly

6 0
3 years ago
Write a single transformation that maps ABC onto A' B' C'
blsea [12.9K]

9514 1404 393

Answer:

  Either of ...

  • (x, y) ⇒ (-x, -y)
  • Rotation 180° about the origin

Step-by-step explanation:

There are at least two ways to express the transformation that maps each coordinate to its opposite.

  1. reflection across the origin: (x, y) ⇒ (-x,-y)

  2. rotation 180° (either direction) about the origin.

Take your pick.

4 0
3 years ago
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
- 1 solve the equation<br> - m - 7 = 5<br> 3
Eduardwww [97]
The answer is 60 because were subtracting in the equation but to find m we need to the opposite which is to add 53 plus 7 which is 60. To check your answer do 60-7 equals 53
3 0
3 years ago
Read 2 more answers
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