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e-lub [12.9K]
3 years ago
8

Find two consecutive odd integers whose product is equal to 63​

Mathematics
1 answer:
valentinak56 [21]3 years ago
8 0

Answer: If you need to see a systematic solution, let the 2 numbers be n and n + 2.

 

n(n + 2) = 63

 

n2 + 2n - 63 = 0

 

(n - 7)(n + 9) = 0

 

n = 7 or -9

 

If n = 7, then n + 2 = 9

If n = -9, then n + 2 = -7

This is based on knowledge of composite numbers: 7 times 9 = 63.

 

The only other pair of numbers satisfying this is -7 and -9

A bit confusing but hopes that helps out somewhat

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B) 2x² - 4x + 3 = 0<br> a) x² + 3x – 10 = 0
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<u>a. x² + 3x – 10</u>

= x² - 2x + 5x - 10

= x (x²/x - 2x/x) + 5 (5x/5 - 2*5/5)

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x - 2 = 0                            x + 5 = 0

 + 2    +2                             -5     -5

--------------                         ---------------

x = 2                                   x = -5

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