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3 years ago

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Tea from Britain costs $2.50 to produce. It is sold in America at a price of $3.50 (to make a profit of $1.00) Tea in America co

sts $3.00 to produce. It is sold at a price of $4.00 (to make a profit of $1.00) If there is a 50% Tariff on tea, who would you buy your tea from?

1 answer:

jok3333 [9.3K]3 years ago

7 0

Answer:

I would buy my tea from Britain.

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Find the coordinates of the point 7/10 of the way from A to B

OverLord2011 [107]

Answer:

(6.8, 1.3)

Step-by-step explanation:

<u>Given</u>:

A(-3, -5), B(11, 4)

<u>Find</u>:

P such that AP/AB = 7/10

<u>Solution</u>:

Using the desired relation, we have ...

(P -A)/(B -A) = 7/10

10(P -A) = 7(B -A) . . . . . multiply by 10(B-A)

10P = 7B +3A . . . . . . . . add 10A to both sides

10P = 7(11, 4) +3(-3, -5) = (77 -9, 28 -15) = (68, 13)

P = (68, 13)/10 = (6.8, 1.3)

The point 7/10 of the way from A to B is (6.8, 1.3).

7 0

2 years ago

You start at (-1, 2). You move right 5 units and down 6 units. Where do you end?

Irina-Kira [14]

Answer:

(4,-4)

Step-by-step explanation:

Just plot it or like I did it like this

Since moving right or left is X axis, just add 5 to -1 becuase its ont he X axis

Then for the bottom and up, thats Y so subtract that to the Y axis so 2-6=-4

4,-4

5 0

2 years ago

-<br> The expression x² - 5 is prime.<br> Is it true or false

lana [24]

Answer:

false

Step-by-step explanation:

X squared minus 5 is not necessarily prime

7 0

2 years ago

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$

Therefore,

$\frac{1}{r} \ln |rA+P| = t+c$

Multiply both sides by $r.$

$\ln |rA+P| = rt+c_1, \quad c_1 := rc$

By taking exponents, we obtain

$e^{\ln |rA+P|} = e^{rt+c_1} \implies |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}$

Isolate $A$ .

$rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}$

Since $A = 0$ when $t=0$ , we obtain an initial condition $A(0) = 0$ .

We can use it to find the numeric value of the constant $c$ .

Substituting $0$ for $A$ and $t$ in the equation gives

$0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P$

Therefore, the solution of the given differential equation is

$A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)$

4 0

2 years ago

Selam purchased a pen at 20% discount on marked price but sold it at marked price find the grain per cent of the Saleem on the t

kiruha [24]

Answer:

25%

Step-by-step explanation:

let the Market Price of the Watch (M.P.) be x

CP for Rahim=x-[(20/100)*x]

CP = (1 *x) /5 = 4x/5

SP for Rahim = MP = x

Difference (Profit) = SP-CP = x - (4x/5) = (5x - 4x)/5 = x/5

Profit % = (Profit/CP) * 100

Profit % = (x/5)/(4x/5) * 100

Profit % = 25 %

7 0

1 year ago