Answer:
16% probability that a randomly chosen U.S. adult sleeps more than 8.7 hours per night
Step-by-step explanation:
The Empirical Rule(Standard Deviation) states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 7.5
Standard deviation = 1.2
Using the Standard Deviation Rule, what is the probability that a randomly chosen U.S. adult sleeps more than 8.7 hours per night?
8.7 = 7.5 + 1.2
So 8.7 is one standard deviation above the mean.
By the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean. The other 100-68 = 32% are more than one standard deviation from the mean. Since the normal probability distribution is symmetric, 16% are more than one standard deviation below the mean and 16% are more than one standard deviation above the mean(above 8.7 hours)
So, 16% probability that a randomly chosen U.S. adult sleeps more than 8.7 hours per night
Answer: A. An OPEN circle on the number 5 and an arrow shading to the RIGHT.
Answer:
The solution to the algebra equation is 4.
Step-by-step explanation:
We are given the equation 5+2b=13. We need to isolate the variable.
First, use subtraction property of equality and subtract 5 from both sides of the equation.
Thus, 2b=8
Now, use division property of equality and divide both sides of the equation by 2.
All things put into consideration, the solution to the algebra equation is 4.
I hope this helped!!
~ Penny
75% would be the percentage of 75/100 students because 100 is the percent and 75 of 100 is 75%.
<span> (3•19x5)
Simplify ————————
19x2
</span>Dividing exponential expressions :
<span> 3.1 </span> <span> x5</span> divided by <span>x2 = x(5 - 2) = x3</span>
Canceling Out :
<span> 3.2 </span> Canceling out <span>19 </span> as it appears on both sides of the fraction line
Final result :<span> 3x<span>3</span></span>
