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Bingel [31]
3 years ago
5

Ma poate ajuta cineva pls!

Mathematics
1 answer:
guapka [62]3 years ago
3 0
Me no understand spanish buddy
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Evaluate y = 2x + 1 when x = 1
Solnce55 [7]

Answer:

y = 3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

y = 2x + 1

x = 1

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                    y = 2(1) + 1
  2. Multiply:                               y = 2 + 1
  3. Add:                                     y = 3
5 0
2 years ago
Find the point in the first octant where the tangent plane to x2+116y2+14z2=1 is parallel to the plane x+y+z=10
Stella [2.4K]
2x+3=yx bc it makes the most sence
7 0
3 years ago
What is the fewest number of quarters, nickels, and pennies that can be fairly exchanged for 2 quarters, 6 nickels, and 9 pennie
adoni [48]

Answer:

Your answer is 3 quarters, 2 nickels, and 4 pennies

Step-by-step explanation:

2 quarters plus 6 nickels plus 9 pennies is equal to 89 cents. So if we subtract 75(3 quarters) we get 14 which is less than 25 therefore we must only use nickels and pennies from now on. If we take 14 and subtract 10(2 nickels) we get 4 which less than 5 leaving us only to use pennies, which one a piece so it must be 4 pennies. Hope this helps!

4 0
3 years ago
If tan e = 1.3, what is the value of cot (90° - 9)?
ella [17]

Answer:

A

Step-by-step explanation:

We are given that:

\tan(\theta)=1.3

And we want to find:

\cot(90^\circ -\theta)

Remember that tangent and cotangent are co-functions. In other words, they follow the cofunction identities:

\tan(\theta)=\cot(90^\circ-\theta)\text{ and } \cot(90^\circ-\theta)=\tan(\theta)

Therefore, since tan(θ) = 1.3 and cot(90° - θ) = tan(θ), then cot(90° - θ) must also be 1.3.

Our answer is A.

7 0
3 years ago
Solve the following word problems​
kirill [66]

Answer:

Step-by-step explanation:

Cost price (CP) = Purchase amount + amount spend on repairing

                        = 85000 + 5000

                        = ₹ 90000

Profit % = 10%

SP = \frac{100+Profit}{100}*CP\\\\=\frac{100+10}{100}*90000\\\\ = \frac{110}{100}*90000

= ₹ 99000

8 0
3 years ago
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