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3 years ago

Solve (2^2x+1)-9(2^x)+4=0

Mathematics

1 answer:

BartSMP [9]3 years ago

8 0

Answer:

x₁ = - 1

x₂ = 2

Step-by-step explanation:

2²ˣ⁺¹ - 9ₓ2ˣ + 4 = 0

2²ˣₓ2 - 9ₓ2ˣ + 4 = 0

2ˣ = n

2n² - 9n + 4 = 0

2n² - n - 8n + 4 = 0

n(2n - 1) - 4(2n - 1) = 0

(2n - 1)(n -4) = 0

2n - 1 = 0 => n₁ = 1/2

n - 4 = 0 => n₂ = 4

2ˣ = 1/2 => 2ˣ = 2⁻¹ => x₁ = - 1

2ˣ = 4 => 2ˣ = 2² => x₂ = 2

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Solve (2^2x+1)-9(2^x)+4=0​

Solve (2^2x+1)-9(2^x)+4=0