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The equation equivalent to this formula would be D)b1=2A-b2
Answer:
the rate of change of the water depth when the water depth is 10 ft is; 
Step-by-step explanation:
Given that:
the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.
We are meant to find the rate of change of the water depth when the water depth is 10 ft.
The diagrammatic expression below clearly interprets the question.
From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t
Then the similar triangles ΔOCD and ΔOAB is as follows:
( similar triangle property)


h = 2.5r

The volume of the water in the tank is represented by the equation:



The rate of change of the water depth is :

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec
Then,

Therefore,

the rate of change of the water at depth h = 10 ft is:




Thus, the rate of change of the water depth when the water depth is 10 ft is; 
Hello!
You can break this down
If she added 8 to the number
x + 8
Multiplied the sum by 2
2(x + 8)
it would equal 6
2(x + 8) = 6
The answer is B
Hope this helps!
The difference between both unit rates rounded off to the nearest tenth is: 0.4 meters per second
Step-by-step explanation:
We have to calculate his unit rate for both type of races
So,
<u>Unit rate for 400m race:</u>
Distance = 400m
Time = 43 sec

<u>Unit rate for 300m Race:</u>
Distance = 300m
Time = 31 sec

The difference between both unit rates is:

Hence,
The difference between both unit rates rounded off to the nearest tenth is: 0.4 meters per second
Keywords: Unit rate, Speed
Learn more about unit rate at:
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