The point P(–4, 4) that is
of the way from A to B on the directed line segment AB.
Solution:
The points of the line segment are A(–8, –2) and B(6, 19).
P is the point that bisect the line segment in
.
So, m = 2 and n = 5.
![x_1=-8, y_1=-2, x_2=6, y_2=19](https://tex.z-dn.net/?f=x_1%3D-8%2C%20y_1%3D-2%2C%20x_2%3D6%2C%20y_2%3D19)
By section formula:
![$P(x, y)=\left(\frac{mx_2+nx_1}{m+n}, \frac{my_2+ny_1}{m+n}\right)](https://tex.z-dn.net/?f=%24P%28x%2C%20y%29%3D%5Cleft%28%5Cfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D%2C%20%5Cfrac%7Bmy_2%2Bny_1%7D%7Bm%2Bn%7D%5Cright%29)
![$P(x, y)=\left(\frac{2\times 6+5\times (-8)}{2+5}, \frac{2\times 19+5\times (-2)}{2+5}\right)](https://tex.z-dn.net/?f=%24P%28x%2C%20y%29%3D%5Cleft%28%5Cfrac%7B2%5Ctimes%206%2B5%5Ctimes%20%28-8%29%7D%7B2%2B5%7D%2C%20%5Cfrac%7B2%5Ctimes%2019%2B5%5Ctimes%20%28-2%29%7D%7B2%2B5%7D%5Cright%29)
![$P(x, y)=\left(\frac{12-40}{7}, \frac{38-10}{7}\right)](https://tex.z-dn.net/?f=%24P%28x%2C%20y%29%3D%5Cleft%28%5Cfrac%7B12-40%7D%7B7%7D%2C%20%5Cfrac%7B38-10%7D%7B7%7D%5Cright%29)
![$P(x, y)=\left(\frac{-28}{7}, \frac{28}{7}\right)](https://tex.z-dn.net/?f=%24P%28x%2C%20y%29%3D%5Cleft%28%5Cfrac%7B-28%7D%7B7%7D%2C%20%5Cfrac%7B28%7D%7B7%7D%5Cright%29)
P(x, y) = (–4, 4)
Hence the point P(–4, 4) that is
of the way from A to B on the directed line segment AB.
Answer:
-3/4, -1/2, -2/5
Step-by-step explanation:
-1/2 = -0.5 = -10/20
-3/4 = -0.75 = -15/20
-2/5 = -0.4 = -8/20
Answer:
45 to 18 it's easy
Step-by-step explanation:
subtract 18 from 63 and there is your ratio
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