A certain law firm consists of 4 senior partners and 6 junior partners. How many different groups of 3 partners can be formed in
which at least one member of the group is a senior partner?
1 answer:
Answer:100
Step-by-step explanation:
There are ten total people:
10C3
10!/(7!×3!) = 120
Note: but that includes all the cases where there are no senior partners
So firstly let figure out the number of cases where there are no senior partners
because there are 6 junior partners
6C3
= 6!/(3!×3!) = 20
120 - 20 = 100 or the number of possible groups where there is at least 1 senior partner.
You might be interested in
A, c, d, f
hope this helps you :)
$235.94 - 80 = 155.94
155.94 ÷ 25.99 = 6
He bought 6 sweaters
Answer:
You click on the crown button near the thanks/heart button
Step-by-step explanation:
6p+p+2-3=8p-8
7p-1=8p-8
1=1p-8
7=1p
p=7
Answer:
Step-by-step explanation:
a.
4 people can be selected in ways=12 P4=12×11×10×9=11880
b.
4 women can be selected in ways=7P4=7×6×5×4=840
c.
