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victus00 [196]
3 years ago
14

A certain law firm consists of 4 senior partners and 6 junior partners. How many different groups of 3 partners can be formed in

which at least one member of the group is a senior partner?
Mathematics
1 answer:
lina2011 [118]3 years ago
8 0

Answer:100

Step-by-step explanation:

There are ten total people:

10C3

10!/(7!×3!) = 120

Note: but that includes all the cases where there are no senior partners

So firstly let figure out the number of cases where there are no senior partners

because there are 6 junior partners

6C3

= 6!/(3!×3!) = 20

120 - 20 = 100 or the number of possible groups where there is at least 1 senior partner.

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