1. John Locke
Just learned about this in global lol
I believe the answer is A, I may be wrong but I’m fairly confident
Good luck :)
Answer:
4tbs
Explanation:
A 75-lb dog must be dewormed. If the daily dose of the dewormer is 1 tsp/25 lb of body weight for 3 days, approximately how much should be given each day?
1 tbs = 3 tsp
answer: 1 tbs
It takes 21.3 days
<h3>Further explanation</h3>
Given
5 hr = 8 kg Alcohol
Required
Days to consume 1000 kg of glucose
Solution
Alcoholic fermentation⇒ glucose produces ethanol and carbon dioxide,
C₆H₁₂O₆ → 2 C₂H₅OH + 2CO₂
mol ethanol :
![\tt \dfrac{5000~g}{46~g/mol}=108.7~moles](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B5000~g%7D%7B46~g%2Fmol%7D%3D108.7~moles)
moles of glucose to produce 108.7 moles ethanol :
![\tt \dfrac{1}{2}\times 108.7=54.35](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20108.7%3D54.35)
54.35 moles = 5 hours
moles of 1000 kg of glucose :
![\tt \dfrac{10^6~g}{180~g/mol}=5555.5~moles](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B10%5E6~g%7D%7B180~g%2Fmol%7D%3D5555.5~moles)
So for 5555.5 moles, it takes :
![\tt \dfrac{5555.5}{54.35}\times 5~hours=511.085~h=21.3~days](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B5555.5%7D%7B54.35%7D%5Ctimes%205~hours%3D511.085~h%3D21.3~days)