Question

Given the specific heat for aluminum is 0.900 J/g.°C, how much heat is released when a 3.8 g sample

Answer 1

Answer:

Q = 1.5 kJ

Explanation:

It is given that,

The specific heat for aluminum is 0.900 J/g°C

Mass of sample, m = 3.8 g

Initial temperature, $T_i=450^{\circ} C$

Final temperature, $T_f=25^{\circ} C$

We need to find the heat released. The amount of heat released is given by the formula:

$Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\Q=3.8\times 0.9\times (25-450)\\\\Q=1453.5\ J\\\\Q=1.45\ kJ$

or

$Q=1.5\ kJ$

So, the correct option is (A) i.e. 1.5 kJ.