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OleMash [197]
3 years ago
5

What is the most important monosaccharide on Earth?

Chemistry
1 answer:
Nikolay [14]3 years ago
5 0
Probably the most important monosaccharide on earth is Glucose. it is used in many bodily functions and it a key source of energy

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What is the mass for 3.01*10 23 molecules h2o
Genrish500 [490]
<em>M H₂O: 1g×2 + 16g = 18g
</em>

6,02×10²³ --------- 18g
3,01×10²³ --------- Xg
X = (18×3,01×10²³)/<span>6,02×10²³
<u>X = 9g

</u>:)
</span>
7 0
4 years ago
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What is the sum of the coefficients needed to balance the combustion reaction of methane?
pishuonlain [190]

Answer:  The sum of the coefficients needed to balance the combustion reaction of methane is 6.

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The chemical equation for combustion of methane will be :

CH_4+2O_2\rightarrow CO_2+2H_2O

The coefficient foer methane is 1 , 2 for oxygen , 1 for carbon dioxide and 2 for water. The sum is 6.

4 0
3 years ago
Using a graduated cylinder, fill a 600 mL beaker with 100 mL of water.
fomenos

Answer:

Temperature of water: 3

Reaction time: 138.5

Explanation:

Your welcome

5 0
4 years ago
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. An element has the electronic structure 2,8, 4. Which group is it in?
Rama09 [41]

Answer:

Ans A

Explanation:

no. of shells determine the group

6 0
3 years ago
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What volume of ammonia gas, measured at 547.9 mmHg and 27.6oC, is required to produce 8.98 g of ammonium sulfate according to th
Studentka2010 [4]

Answer:

4.65 L of NH₃ is required for the reaction

Explanation:

2NH₃(g)  +  H₂SO₄(aq)  → (NH₄)₂SO₄(s)

We determine the ammonium sulfate's moles that have been formed.

8.98 g . 1mol / 132.06 g = 0.068 moles

Now, we propose this rule of three:

1 mol of ammonium sulfate can be produced by 2 moles of ammonia

Therefore, 0.068 moles of salt were produced by (0.068 . 29) / 1 = 0.136 moles of NH₃. We apply the Ideal Gases Law, to determine the volume.

Firstly we do unit's conversions:

27.6°C +273 =  300.6 K

547.9 mmHg . 1 atm / 760 mmHg = 0.721 atm

V = ( n . R . T ) / P → (0.136 mol . 0.082 L.atm/mol.K . 300.6K) / 0.721 atm

V = 4.65 L

4 0
3 years ago
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