Which three of the following are steps of aerobic cellular respiration?

What mass of al is required to completely react with 25.0 grams of mno2?

horsena [70]

Mass of MnO2 = 25 g
The reaction would be 3MnO2 + 4Al --> 3Mn(s) + 2Al2O3
Molar mass of Al = 26.982 g/mol
Molar mass of MnO2 = 54.938 + 2(15.999) = 86.936 g/mol
Calculating the moles = 25 / 86.936 = 0.2876 mol.
Mole ratio MnO2 and Al considering the equation = 3 mol of MnO : 4 mol of Al
Calculating the moles of Al = 0.2876 mol MnO2 x (4 mol of Al / 3 mol of MnO)
Number of moles of Al = 0.3834
Getting the mass in grams as asked = 0.3834 mol x 26.982 g/mol = 10.34 grams.

6 0

3 years ago

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MnO2 + 4HCl reacts to form MnCl2 + CL2 + 2H2O If .86 mol of MnO2 and 48.2 g of HCl react, which reactant is the limiting reagent

Katen [24]

HCl:
<span>
m=48,2g
M=36,5g/mol

n = m/M = 48,2g / 36,5g/mol = 1,32mol

1mol : 4mol
MnO</span>₂ + 4HCl ⇒ MnCl₂ + Cl₂ + 2H₂O
0,86mol : 1,32mol
limiting reagent
0,33 will react

HCl is limiting reagent.

6 0

3 years ago

An oxide of P contains 50% by mass of P. Its Relative molecular mass is 64. The molecular formula of the oxide is (P=32; O=16)

anygoal [31]

Answer:

B) PO2

Explanation:

first solve empirical formula

50%of P and 50%of O

divide each by molecular mass

P. O

50/32. 50/16

1.5. 3.0

divide both by the smallest

1.5/1.5. 3.0/1.5

1. :. 2

Empirical formula=PO2

Molecular formula=PO2

(PO2)n= 64

(32+(16×2)=64

(32+32)n=64

64n=64

n= 1

5 0

3 years ago

How many liters of 0.37 M solution can be made with 29.53 grams of lithium fluoride.<br> (LiF)?

dsp73

Answer:

V = 3.1 L

Explanation:

Given data:

Molarity of solution = 0.37 M

Mass of LiF = 29.53 g

Volume of solution = ?

Solution:

Number of moles of LiF:

Number of moles = mass/molar mass

Number of moles = 29.53 g/ 25.94g/mol

Number of moles = 1.14 mol

Volume:

Molarity = number of moles of solute / Volume in L

0.37 M = 1.14 mol / V

V = 1.14 mol / 0.37 M

V = 3.1 L (M = mol/L)

4 0

3 years ago

Which would be the best way to represent the concentration of a 1. 75 M K2CrO4 solution? 1. 75% K2CrO4 [K2CrO4] (K2CrO4) K2CrO4,

tekilochka [14]

The amount of the solute present in the given solution is called the concentration. The best way to represent the concentration of the solution is $\rm [K_{2}CrO_{4}].$

<h3>What is molar concentration?</h3>

Molar concentration is the molarity of the solution that is the measure of the concentration of the solute dissolved in the solution.

The formula for calculating molar concentration is given as,

$\rm Molarity = \dfrac{\text{moles of solute}}{\text{Solution in L}}$

The concentration of any substance is represented in the square bracket like $\rm [X]$ or $\rm [K_{2}CrO_{4}].$

Therefore, option B. $\rm [K_{2}CrO_{4}]$ is the representation of the concentration.

Learn more about the molarity here:

brainly.com/question/1532164

8 0

2 years ago