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andrew-mc [135]
3 years ago
6

A helicopter blade spins at exactly 100 revolutions per minute. Its tip is 5.00 m from the center of rotation. (a) Calculate the

average speed of the blade tip in the helicopter’s frame of reference. (b) What is its average velocity over one revolution?\
Physics
1 answer:
professor190 [17]3 years ago
7 0

Explanation:

It is given that,

A helicopter blade spins at exactly 100 revolutions per minute.

Its tip is 5.00 m from the center of rotation, r = 5 m

(a) Let v is the average speed of the blade tip in the helicopter’s frame of reference. Distance covered by the helicopter, d=2\pi r

In 100 revolutions, d=200\pi r=1000\pi

So, average speed of the blade tip in one second is given by :

v=\dfrac{d}{t}

v=\dfrac{1000\pi\ m}{60\ s}

v = 52.35 m/s

(b) The average velocity over one revolution is zero because the net displacement in one rotation is 0.

Hence, this is the required solution.

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