5. How many kilowatt-hours of energy would be used by a 40 W bulb that runs for 10 hours every
1 answer:
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Answer:
(a) Acceleration of positron is 6.03 x 10¹³ m/s²
(b) Speed of positron after 8.70 x 10⁻⁹ s is 5.24 x 10⁵ m/s
Explanation:
Given :
Constant electric field, E = 343 N/C
Mass of positron, m = 9.1 x 10⁻³¹ kg
Charge of positron, q = +e = 1.6 x 10⁻¹⁹ C
(a) Coulomb force on the positron is determine by the relation :
F = q x E ....(1)
But, force is also equals to product of mass and acceleration. So,
F = ma .....(2)
Here a is acceleration.
From equation (1) and (2).
m x a = q x E
Substitute the values of q, E and m in the above equation.
a = 6.03 x 10¹³ m/s²
(b) Initially, the positron is at rest, so its initial speed is zero.
The equation of motion for positron is :
v = u + at
Here v is final speed, u is initial speed and t is time.
Since, u is zero, so the equation becomes :
v = at
Substitute 8.70 x 10⁻⁹ s for t and 6.03 x 10¹³ m/s² for a in the above equation.
v = 6.03 x 10¹³ x 8.70 x 10⁻⁹ m/s
v = 5.24 x 10⁵ m/s
Answer:
a
The mass is
b
The velocity is
Explanation:
From the question we are told that
The speed of the protons is
The mass of the protons is
The speed of the rebounding protons are
The negative sign shows that it is moving in the opposite direction
Now according to the law of energy conservation mass of one nucleus of the unknown element. is mathematically represented as
Where is the mass of a single proton
So substituting values
The mass of on proton is
So
Now according to the law of linear momentum conservation the speed of the unknown nucleus immediately after such a collision is mathematically evaluated as
Now because before collision the the nucleus was at rest
So
=>
Recall that
So
=>
substituting values