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cricket20 [7]
3 years ago
13

PLEASE HELP WILL MAKE BRAINIEST (GIVING AWAY 20 POINTS)

Physics
1 answer:
Bond [772]3 years ago
5 0

1) The most potential energy is at position A

2) The most kinetic energy is at position C

Explanation:

1)

The gravitational potential energy is the energy possessed by an object due to its position in a gravitational field, and it is given by the equation

PE=mgh

where

m is the mass of the object

g is the acceleration of gravity

h is the height of the object relative to the ground

From the equation, we see that the potential energy is directly proportional to the heigth of the object: therefore, the roller coaster in this problem will have the most potential energy at its highest postion, so at position A.

2)

The total mechanical energy of the roller coaster at any point along the track is given by

E=PE+KE

where

PE is the potential energy

KE is the kinetic energy

Assuming there is no friction, the mechanical energy E is constant. This means that when PE increases, KE decreases, and when PE increases, KE decreases.

Therefore, the cart will have maximum kinetic energy when the potential energy is at minimum: and since the potential energy is directly proportional to the height of the track, this will occur at the lowest position, so at position C.

Learn more about kinetic and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

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Two long, parallel wires carry currents of different magnitudes. If the amount of current in one of the wires is doubled, what h
Ulleksa [173]

Answer:

The magnitude of the force that each wire exerts on the other will increase by a factor of two.

Explanation:

force on parallel current carrying wire, F = BILsinθ

where;

B is the strength of the magnetic field

L is the length of the wire

I is the magnitude of current on the wire

θ is the angle of inclination of the wire

Assuming B, L and θ is constant, then F ∝ I

F = kI

\frac{F_1}{I_1} = \frac{F_2}{I_2}

When the amount of current is doubled in one of the wires, lets say the second wire;

\frac{F_1}{I_1} = \frac{F_2}{2I_1} \\\\F_2 = \frac{2F_1I_1}{I_1} \\\\F_2 =2F_1

Also, if will double the amount of current on the first wire, then

F₁ = 2F₂

Therefore, the magnitude of the force that each wire exerts on the other will increase by a factor of two.

3 0
3 years ago
A- what constant acceleration, in SI units, must a car have to gofrom zero to 60 mph in 10 s?
umka2103 [35]

Answer:

(a) 0.017m/s^2

(b) 17/100,000

(c) 0.17m, 0.558ft

Explanation:

(a) speed = 60mph = 60m/1h × 1h/3600s = 0.017m/s, time = 10s

Acceleration (a) = speed ÷ time = 0.017m/s ÷ 10s = 0.0017m/s^2

(b) g = 9.8m/s^2, a = 0.0017m/s^2

a/g = 0.0017/9.8 = 0.00017 = 17/100,000

(c) Distance = speed × time = 0.017m/s × 10s = 0.17m

Distance in foot = 0.17 × 3.2808ft = 0.558ft

3 0
3 years ago
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Please help answer much as possible there's 4 questions
katovenus [111]

Answer:

6. A

7. A

9. B

hope dis helps ^-^

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3 years ago
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In order for a living organism to sustain its life, it must be able to
maw [93]

Answer:

All living organisms have complex organization, they are able to grow and develop, they are able to reproduce and pass on genetic information to their offspring, they are able to acquire and release energy, and they are able to maintain stable internal environments.

Explanation:

7 0
2 years ago
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Polonium, the Period 6 member of Group 6A(16), is a rare radioactive metal that is the only element with a crystal structure bas
Burka [1]

Answer:

Approximate atomic radius for polonium-209 is 167.5 pm .

Explanation:

Number of atom in simple cubic unit cell = Z = 1

Density of platinum = 9.232 g/cm^3

Edge length of cubic unit cell= a = ?

Atomic mass of Po (M) = 209 g/mol

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

ρ = density

Z = number of atom in unit cell

M = atomic mass

(N_{A}) = Avogadro's number  

a = edge length of unit cell

On substituting all the given values , we will get the value of 'a'.

9.232 g/cm3=\frac{1 \times 209 g/mol}{6.022\times 10^{23} mol^{-1}\times (a)^{3}}

a = 3.35\times 10^{-8} cm

Atomic radius of the polonium in unit cell = r

r = 0.5a

r=0.5\times 3.35\times 10^{-8} cm=1.675\times 10^{-8} cm

1 cm = 10^{10} pm

1.675\times 10^{-8} cm=1.675\times 10^{-8}\times 10^{10}=167.5 pm

Approximate atomic radius for polonium-209 is 167.5 pm.

7 0
3 years ago
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