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4 years ago

PLEASE HELP WILL MAKE BRAINIEST (GIVING AWAY 20 POINTS)

Physics

1 answer:

Bond [772]4 years ago

5 0

1) The most potential energy is at position A

2) The most kinetic energy is at position C

Explanation:

The gravitational potential energy is the energy possessed by an object due to its position in a gravitational field, and it is given by the equation

$PE=mgh$

where

m is the mass of the object

g is the acceleration of gravity

h is the height of the object relative to the ground

From the equation, we see that the potential energy is directly proportional to the heigth of the object: therefore, the roller coaster in this problem will have the most potential energy at its highest postion, so at position A.

The total mechanical energy of the roller coaster at any point along the track is given by

$E=PE+KE$

where

PE is the potential energy

KE is the kinetic energy

Assuming there is no friction, the mechanical energy E is constant. This means that when PE increases, KE decreases, and when PE increases, KE decreases.

Therefore, the cart will have maximum kinetic energy when the potential energy is at minimum: and since the potential energy is directly proportional to the height of the track, this will occur at the lowest position, so at position C.

Learn more about kinetic and potential energy:

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A Hooke's law bowstring is stretched x meters until a force of f newtons is applied, and then held. By what factor will the elas

Liono4ka [1.6K]

The elastic potential energy increases by a factor of 9

Explanation:

The elastic potential energy of a bowstring is given by

$E=\frac{1}{2}kx^2$ (1)

where

k is the spring constant

x is the elongation of the bowstring

Hooke's law states the relationship between the force applied and the elongation of an elastic object:

$F=kx$

where

F is the force applied

x is the elongation

We can rewrite it as

$x=\frac{F}{k}$

And substituting into (1),

$E=\frac{1}{2}k(\frac{F}{k})^2=\frac{F^2}{2k}$

In this problem, the force applied to the bowstring is tripled,

F' = 3F

So the final elastic potential energy is:

$E'=\frac{(3F)^2}{2k}=9(\frac{F^2}{2k})=9E$

So, the elastic potential energy increases by a factor of 9.

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3 years ago

Why does an object roll faster down a steeper hill than a not so steep hill.

Natasha2012 [34]

The answer is : <span>Gravity draws an object towards its strongest point. The main things holding you back are air resistance and friction. As a hill gets steeper, you are more in line with the center of gravity, so it overcomes friction and you move faster. Eventually when you are moving vertically there is no friction other than air resistance itself. At this time you will accelerate at 32 feet per second every second until you either hit something or reach terminal velocity which is around 120 mph. Air resistance (on the Earth at least) will not allow you to travel any faster. Hope this Helped! Good Luck! :)</span>

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3 years ago

The Force Of Gravity Acting On A Childs Mass On Earth Is 490 newtons whats the childs mass

Flauer [41]

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4 years ago

Boyle’s Law states that when a sample of gas is compressed at a constant temperature, the pressure P of the gas is inversely pro

jolli1 [7]

Answer:

a) $V=\dfrac{5.3}{P}$