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Lynna [10]
2 years ago
6

What is the role of MnO2 in a dry cell?​

Physics
1 answer:
padilas [110]2 years ago
7 0

Answer:MNO2 is a depolarizer in a dry cell

Explanation:

MNO2 is depolarizer in a dry cell. depolarizers are chemicals used to reduce or prevent polarization of cells

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A man pushes on piano with mass 170 kg; it slides at constant velocity down a ramp that is inclined at 20.0 ∘ above the horizont
nikdorinn [45]

Answer

given,                            

mass of the piano = 170 kg              

angle of the inclination = 20°                

moves with constant velocity hence acceleration = 0 m/s²    

neglecting friction                                  

so, force required to pull the piano                    

F = m g sin θ                                                      

F = 170 × 9.81 × sin 20°                                        

F = 570.39 N                                                    

so, force required by the man to push the piano is F = 570.39 N

4 0
2 years ago
What is pitch related to?
Jlenok [28]
Pitch is related to frequency
7 0
3 years ago
if a ball with an original velocity of 0 is dropped from a tall structure and takes 7 Seconds to hit the ground what velocity do
krok68 [10]

a_y=\dfrac{v_y-v_{0y}}t\implies-9.81\,\dfrac{\mathrm m}{\mathrm s^2}=\dfrac{v_y-0}{7\,\mathrm s}\implies v_y=-68.7\,\dfrac{\mathrm m}{\mathrm s}

5 0
3 years ago
Your iclicker operates at a frequency of approximately 900 mhz (900x106 hz). what is the approximate wavelength of the em wave p
Umnica [9.8K]
The clicker emits EM (electromagnetic) wave which travels at the speed of light, that is
v = 3 x 10⁸ m/s

The frequency is
f = 900mHz = 9 x 10⁸ Hz

Because velocity = frequency * wavelength, the wavelength, λ,  is given by
fλ = v
λ = v/f
   = (3 x 10⁸ m/s) / (9 x 10⁸ 1/s)
   = 1/3 m

Answer:  1/3 m

5 0
2 years ago
A balloon is ascending at a rate of +4.00 m/s to a height of 11.0 m above the ground when a package is dropped. In the absence o
o-na [289]

Answer:

Vf = 14.7 m/s

Explanation:

Vf² = Vi² + 2 * a * Δy

given:

a = 9.81 m/s²

Δy = 11m

Vi = 0 when upon release

Vf² = 0 + 2 (9.81) 11

Vf = 14.7 m/s

6 0
3 years ago
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