A copper wire of length 4.00 cm and radius 4.00 mm has a potential difference of 4.00 nV across the ends of the wire. Calculate
the amount of charge in microCoulombs) drifting through the cross section in 4.00 ms. Assume the resistivity of copper is 1.70 x 10-8 Ohm-meters.
1. 101.88
2. 1.18
3. 0.59
4. 41.40
5. 66.35 [10 points]
1. 101.88
2. 1.18
3. 0.59
4. 41.40
5. 66.35 [10 points]
1 answer:
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(a) 7.9 s
The period of a wave is time that passes between two consecutive crests (or two consecutive troughs).
In this case, we are told that five crests pass in a time of 39.5 s. Therefore we can find the period by using the proportion:
Where T is the period. Re-arranging the equation, we find
(b) 0.127 Hz
The frequency of a wave is equal to the reciprocal of the period:
where
f is the frequency
T is the period
For this wave, we have T = 7.9 s, so its frequency is
(c) 37.9 m
The wavelength of a wave is the distance between two consecutive crests (or two consecutive troughs). For this wave, the distance between two successive crests is 37.9 m, so the wavelength of the wave is
(d) 4.81 m/s
The speed of a wave is given by
where
is the wavelength
f is the frequency
For the wave in the problem, we have
Therefore, the speed of the wave is