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xxMikexx [17]
3 years ago
10

A copper wire of length 4.00 cm and radius 4.00 mm has a potential difference of 4.00 nV across the ends of the wire. Calculate

the amount of charge in microCoulombs) drifting through the cross section in 4.00 ms. Assume the resistivity of copper is 1.70 x 10-8 Ohm-meters.
1. 101.88
2. 1.18
3. 0.59
4. 41.40
5. 66.35 [10 points]

Physics
1 answer:
Marrrta [24]3 years ago
5 0

Answer: The amount of charge in microCoulombs is 1.18 ( Q = 1.18µC).

The correct option is 2

Explanation: Please see the attachments below

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7 0
3 years ago
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An electric motor consumes 8.40 kJ of electrical energy in 1.00 min. Part A If one-third of this energy goes into heat and other
Salsk061 [2.6K]

Answer:

The torque is 0.31 Nm.

Explanation:

Electrical energy, E = 8400 J

time, t = 1 min

Angular speed, w = 2900 rpm = 303.53 rad/s

efficiency = 2/3 of input power

The toque is given by  

P =\tau  w\\\\\frac{2}{3}\times \frac{E}{t}=\tau w\\\\\frac{2}{3}\times \frac{8400}{60}=\tau \times 303.53\\\\\tau =0.31 Nm

3 0
3 years ago
2. Can you place three forces of 5g, 6g, and 12g so they are in equilibrium. Justify your answer.
Bond [772]

Answer:

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

Explanation:

Equilibrium means their sum must be zero.

Here the forces are 5g, 6g, and 12g.

For number of forces to be in equilibrium the magnitude of largest vector should be less than sum of the magnitude of other vectors.

Here

        Magnitude of largest force = 12 g

        Sum of magnitudes of other forces = 5g + 6g = 11g

       Magnitude of largest force >   Sum of magnitudes of other forces

So this forces cannot form equilibrium.

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

4 0
3 years ago
Which characteristics of rocks are used in classification? Check all that apply.
Elanso [62]

Answer:

i think it is texture and composition

3 0
3 years ago
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I have a question regarding friction in rolling without slipping.
Solnce55 [7]

Explanation:

They probably put "rolls without slipping" in there to indicate that there is no loss in friction; or that the friction is constant throughout the movement of the disk. So it's more of a contingency part of the explanation of the problem.

(Remember how earlier on in Physics lessons, we see "ignore friction" written into problems; it just removes the "What about [ ]?" question for anyone who might ask.)

In this case, you can't ignore friction because the disk wouldn't roll without it.

As far as friction producing a torque... I would say that friction is a result of the torque in this case. And because the point of contact is, presumably, the ground, the friction is tangential to the disk. Meaning the friction is linear and has no angular component.

(You could probably argue that by Newton's 3rd Law there should be some opposing torque, but I think that's outside of the scope of this problem.)

Hopefully this helps clear up the misunderstanding for you.

4 0
3 years ago
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