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3 years ago

What is 87+x=100? A. 13 B.41 C. 11 D. 20

Mathematics

2 answers:

Leto [7]3 years ago

8 0

Hey there!

When we solve for x, we need to isolate x on one side.

This is just a one-step equation, meaning there is only one thing we need to do to solve for x, or isolate x.

Starting with 87 + x = 100:

Subtract 87 from each side.

87 - 87 + x = 100 - 87

Simplify. Subtracting 87 from 87 makes it equal to 0.

x = 13

Your answer is A. 13.

Hope this helps!

Gre4nikov [31]3 years ago

5 0

Hello!

The answer to the problem is A) 13

Move all terms containing x to the left, all other terms to the right.

Add '-87' to each side of the equation

$87 + -87 + x = 100 + -87$

Combine like terms: 87 + -87 = 0

$0 + x = 100 + -87$

$x = 100 + -87$

Get your answer

$x=13$

Hope This Helps!

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The solution to x2 – 10x = 24 is

Marat540 [252]

Answer:

x = - 2, x = 12

Step-by-step explanation:

Given

x² - 10 x = 24 ( subtract 24 from both sides )

x² - 10x - 24 = 0 ← in standard form

To factorise the quadratic

Consider the factors of the constant term (- 24) which sum to give the coefficient of the x- term (- 10)

The factors are - 12 and + 2, since

- 12 × 2 = - 24 and - 12 + 2 = - 10, thus

(x - 12)(x + 2) = 0

Equate each factor to zero and solve for x

x - 12 = 0 ⇒ x = 12

x + 2 = 0 ⇒ x = - 2

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2 years ago

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madreJ [45]

Answer:

Step-by-step explanation:

The Answer is

D) The rate of change for function B is greater than the rate of change for function A.

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3 years ago

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bagirrra123 [75]

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Step-by-step explanation:

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2 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

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2 years ago

Carlos has six cards in a bag, numbered 2, 2, 3, 6, 8, and 9. What is the probability Carlos will randomly select a 2 or a 9

AfilCa [17]

Answer:

50 percent

Step-by-step explanation:

100 percent divided by 6 (the amount of data) is 16 2/3.

Each number represents 16 2/3 percent.

3 of the numbers are either 2 or 9.

16 2/3x3=50.001

The final answer is a 50% probability.

I think

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2 years ago