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3 years ago

Can you help with this task please? I don't understand.

Mathematics

1 answer:

dezoksy [38]3 years ago

8 0

Answer:

nota entonces jwbsbsbwhe de un 2

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The area of a rectangular parking lot is 4947 m2.

Sedbober [7]

Answer:

1. width = 51 m

2. length = 84 m

Step-by-step explanation:

So remember, the area is (length * width).

It is given that the length is 97, and the area is 4947.

So plug this into a formula:

length * width = area

97 * width = 4947

Solve using inverse operations;

97 * width = 4947

/97 /97

width = 51m

The perimeter of a rectangle can be found by doing, (2 * (length + width)).

The width is given, it is 68m. The perimeter is also given, 304m. So just form an equation using this information:

2 * ( length + width) = perimeter

2 * (length + 68 ) = 304

Distribute;

2 * ( length + 68) = 304

2 length + 136 = 304

Inverse operations;

2length + 136 = 304

-136 -136

2length = 168

/2 /2

length = 84m

8 0

3 years ago

Read 2 more answers

Kayla is give a monthly allowance. She puts 40% of the money directly into her savings account. She spends $15 at the movies wit

mars1129 [50]

£30
This is because if she has put 40% in to savings she has 60% left. This 60% is 15 + 3 (the money she spent at the movies and the money she has left) = £18
So 60% : £18
10% : £3 (divide by 6)
100% : £30 (multiply by 100)

4 0

4 years ago

Find the absolute maximum and minimum values of the function below. f(x) = x3 − 9x2 + 3, − 3 2 ≤ x ≤ 12 Solution Since f is cont

Neko [114]

Answer:

There are an absolute minimum (x = 6) and an absolute maximum (x = 12).

Step-by-step explanation:

The correct statement is described below:

Find the absolute maximum and minimum values of the function below:

$f(x) = x^{3}-9\cdot x^{2}+ 3$ , $2 \leq x \leq 12$

Given that function is a polynomial, then we have the guarantee that function is continuous and differentiable and we can use First and Second Derivative Tests.

First, we obtain the first derivative of the function and equalize it to zero:

$f'(x) = 3\cdot x^{2}-18\cdot x$