Find the mean for the given set of data.

Mathematics

1 answer:

KIM [24]3 years ago

6 0

A) should be ur answer

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Vadim26 [7]

Answer:

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Step-by-step explanation:

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7 0

3 years ago

Jane has three boxes she needs to ship. Box X weighs 33 kg more than Box Y and Box Z weighs 12 kg more than Box Y. She

andreyandreev [35.5K]

Answer:

$3w+45=557$

Step-by-step explanation:

Let the weight of box Y be w kg.

Box X weighs 33 kg more than Box Y, then the weight of box X is

$w+33$ kg.

Box Z weighs 12 kg more than Box Y, then the weight of box Z is

$w+12$ kg.

The total weight of all boxes is

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Jane measured the total weight of all the boxes and it was found to be 557 kg, therefore,

$3w+45=557$

$3w=512$

3 0

3 years ago

Remember to check for extraneous solutions

larisa86 [58]

$Domain:v\neq0\\\\\dfrac{2}{v}+\dfrac{2}{3}=\dfrac{v-6}{3v}\\\\\dfrac{2\cdot3}{v\cdot3}+\dfrac{2\cdot v}{3\cdot v}=\dfrac{v-6}{3v}\\\\\dfrac{6}{3v}+\dfrac{2v}{3v}=\dfrac{v-6}{3v}\\\\\dfrac{6+2v}{3v}=\dfrac{v-6}{3v}\iff6+2v=v-6\qquad\text{subtract 6 from both sides}\\\\2v=v-12\qquad\text{subtract v from both sides}\\\\\boxed{v=-12}\to\boxed{A.}$